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anonymous

  • 4 years ago

How do I solve this? x^2/3 + 4x^1/3 + 3 = 0

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  1. anonymous
    • 4 years ago
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    Factorize it as : (x^(1/3)+1) (x^(1/3)+3) = 0

  2. anonymous
    • 4 years ago
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    sorry, wrong didn't see the +3

  3. anonymous
    • 4 years ago
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    x never equals zero though... i don't think

  4. anonymous
    • 4 years ago
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    There are no solutions,I suppose

  5. anonymous
    • 4 years ago
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    are you sure you wrote the problem correctly?

  6. anonymous
    • 4 years ago
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    Thanks, I'm still confused...I will retype the question...

  7. Xishem
    • 4 years ago
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    How do you figure that x never equals 0?

  8. anonymous
    • 4 years ago
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    graphing calculator

  9. anonymous
    • 4 years ago
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    @ xishem try substituting x = 0

  10. anonymous
    • 4 years ago
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    Solve the equation. x^2/3 + 4x^1/3 + 3 = 0 I think when solving for x, the equation is set equal to zero...

  11. Xishem
    • 4 years ago
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    \[f(-1)=0\]

  12. anonymous
    • 4 years ago
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    no, it equals 2

  13. anonymous
    • 4 years ago
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    @studioso33 is it x^(2/3)

  14. anonymous
    • 4 years ago
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    IT has no solutions; plot it and see

  15. anonymous
    • 4 years ago
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    it has no solution as written in the real numbers, there are non-real answers however

  16. Xishem
    • 4 years ago
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    \[f(-1)=x^{2/3}+4x^{1/3}+3=(-1)^{2/3}+4(-1)^{1/3}+3=1-4+3=0\]

  17. anonymous
    • 4 years ago
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    SalvatoreTRM, I'm not sure? I've never typed out equations before!

  18. anonymous
    • 4 years ago
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    does it look like Xishem wrote it?

  19. anonymous
    • 4 years ago
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    x= -27 or -1

  20. Xishem
    • 4 years ago
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    I plotted, and there are two solutions.

  21. anonymous
    • 4 years ago
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    Sorry, I'm new here...you guys are far more advanced at math than I! Yes, looks like Xishem wrote it...

  22. anonymous
    • 4 years ago
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    ok then yes, Ireneoseaspe is right and Xishem as well. x=-27 and -1

  23. anonymous
    • 4 years ago
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    Xishem, how to I plot and find solutions myself? Are you all using graphing calculators?

  24. Xishem
    • 4 years ago
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    Why is Wolfram plotting it like this? http://www.wolframalpha.com/input/?i=x%5E%282%2F3%29%2B4x%5E%281%2F3%29%2B3

  25. Xishem
    • 4 years ago
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    @studio: I didn't find the original solutions graphically, but rather by factoring and setting each of the factors equal to zero separately.

  26. anonymous
    • 4 years ago
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    Ok, i take it back, no solutions. Viva wolfram

  27. anonymous
    • 4 years ago
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    Thank you all...it will take time for me to get used to this online tutoring...I will be in here ALOT!

  28. Xishem
    • 4 years ago
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    Wolfram is wrong. Take a look at THIS plot, which is just a factorization of the original. http://www.wolframalpha.com/input/?i=%281%2Bx%5E%281%2F3%29%29+%283%2Bx%5E%281%2F3%29%29&lk=1&a=ClashPrefs_*Math- Both the math and my graphing calculator tell me that there are two solutions.

  29. anonymous
    • 4 years ago
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    http://www.wolframalpha.com/input/?i=cos%5E-1++%28-1%29

  30. anonymous
    • 4 years ago
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    who is wolfram?

  31. Xishem
    • 4 years ago
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    \[(x^{1/3}+1) (x^{1/3}+3) = 0\]\[x^{1/3}+1=0 \rightarrow x^{1/3}=-1 \rightarrow x=(-1)^3 \rightarrow x=-1\]You can't deny that there are solutions.

  32. anonymous
    • 4 years ago
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    @studio website

  33. anonymous
    • 4 years ago
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    If you put x = -1 you get 3 not 0

  34. anonymous
    • 4 years ago
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    x^2/3 + 4x^1/3 + 3 = 0 u=x^1/3 u^2 + 4u + 3 = 0 (u + 3)(u + 1) = 0 u= -3,u= - 1 u=x^1/3 -3 = x^1/3 (-3)^3 = (x^1/3)^3 -27 = x u=x^1/3 -1 = x^1/3 (-1)^3 = (x^1/3)^3 -1 = x

  35. Xishem
    • 4 years ago
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    Aron: Show your work. I get 0 every time.

  36. anonymous
    • 4 years ago
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    @Irene if you substitute the values you wont get 0.

  37. anonymous
    • 4 years ago
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    Xishem, do you know robby mayasich?

  38. anonymous
    • 4 years ago
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    nvm, your profile pic reminded me of someone

  39. Xishem
    • 4 years ago
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    http://www.wolframalpha.com/input/?i=%28-1%29%5E%281%2F3%29 Wolfram also thinks that is true. Weird.

  40. Xishem
    • 4 years ago
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    And that error would explain why WolframAlpha doesn't give the correct answers.

  41. anonymous
    • 4 years ago
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    (x^(1/3)+1) (x^(1/3)+3) = 0

  42. anonymous
    • 4 years ago
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    x^2/3 + 4x^1/3 + 3 = 0 (-27)^2/3 + 4(-27)^1/3 + 3 = 0 \[\sqrt[3]{-27^{2}} + 4\sqrt[3]{-27} + 3 = 0\] \[\sqrt[3]{729} + 4(-3) + 3 = 0\] \[9 -12 + 3 = 0\] \[-3 + 3 =0\] 0=0

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