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anonymous
 4 years ago
How do I solve this?
x^2/3 + 4x^1/3 + 3 = 0
anonymous
 4 years ago
How do I solve this? x^2/3 + 4x^1/3 + 3 = 0

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Factorize it as : (x^(1/3)+1) (x^(1/3)+3) = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry, wrong didn't see the +3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x never equals zero though... i don't think

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0There are no solutions,I suppose

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0are you sure you wrote the problem correctly?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks, I'm still confused...I will retype the question...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How do you figure that x never equals 0?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@ xishem try substituting x = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Solve the equation. x^2/3 + 4x^1/3 + 3 = 0 I think when solving for x, the equation is set equal to zero...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@studioso33 is it x^(2/3)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0IT has no solutions; plot it and see

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it has no solution as written in the real numbers, there are nonreal answers however

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[f(1)=x^{2/3}+4x^{1/3}+3=(1)^{2/3}+4(1)^{1/3}+3=14+3=0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0SalvatoreTRM, I'm not sure? I've never typed out equations before!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0does it look like Xishem wrote it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I plotted, and there are two solutions.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry, I'm new here...you guys are far more advanced at math than I! Yes, looks like Xishem wrote it...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok then yes, Ireneoseaspe is right and Xishem as well. x=27 and 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Xishem, how to I plot and find solutions myself? Are you all using graphing calculators?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Why is Wolfram plotting it like this? http://www.wolframalpha.com/input/?i=x%5E%282%2F3%29%2B4x%5E%281%2F3%29%2B3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@studio: I didn't find the original solutions graphically, but rather by factoring and setting each of the factors equal to zero separately.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok, i take it back, no solutions. Viva wolfram

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you all...it will take time for me to get used to this online tutoring...I will be in here ALOT!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Wolfram is wrong. Take a look at THIS plot, which is just a factorization of the original. http://www.wolframalpha.com/input/?i=%281%2Bx%5E%281%2F3%29%29+%283%2Bx%5E%281%2F3%29%29&lk=1&a=ClashPrefs_*Math Both the math and my graphing calculator tell me that there are two solutions.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[(x^{1/3}+1) (x^{1/3}+3) = 0\]\[x^{1/3}+1=0 \rightarrow x^{1/3}=1 \rightarrow x=(1)^3 \rightarrow x=1\]You can't deny that there are solutions.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If you put x = 1 you get 3 not 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x^2/3 + 4x^1/3 + 3 = 0 u=x^1/3 u^2 + 4u + 3 = 0 (u + 3)(u + 1) = 0 u= 3,u=  1 u=x^1/3 3 = x^1/3 (3)^3 = (x^1/3)^3 27 = x u=x^1/3 1 = x^1/3 (1)^3 = (x^1/3)^3 1 = x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Aron: Show your work. I get 0 every time.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Irene if you substitute the values you wont get 0.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Xishem, do you know robby mayasich?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nvm, your profile pic reminded me of someone

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=%281%29%5E%281%2F3%29 Wolfram also thinks that is true. Weird.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0And that error would explain why WolframAlpha doesn't give the correct answers.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(x^(1/3)+1) (x^(1/3)+3) = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x^2/3 + 4x^1/3 + 3 = 0 (27)^2/3 + 4(27)^1/3 + 3 = 0 \[\sqrt[3]{27^{2}} + 4\sqrt[3]{27} + 3 = 0\] \[\sqrt[3]{729} + 4(3) + 3 = 0\] \[9 12 + 3 = 0\] \[3 + 3 =0\] 0=0
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