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Factorize it as : (x^(1/3)+1) (x^(1/3)+3) = 0

sorry, wrong didn't see the +3

x never equals zero though... i don't think

There are no solutions,I suppose

are you sure you wrote the problem correctly?

Thanks, I'm still confused...I will retype the question...

How do you figure that x never equals 0?

graphing calculator

@ xishem try substituting x = 0

\[f(-1)=0\]

no, it equals 2

@studioso33 is it x^(2/3)

IT has no solutions; plot it and see

it has no solution as written in the real numbers, there are non-real answers however

\[f(-1)=x^{2/3}+4x^{1/3}+3=(-1)^{2/3}+4(-1)^{1/3}+3=1-4+3=0\]

SalvatoreTRM, I'm not sure? I've never typed out equations before!

does it look like Xishem wrote it?

x= -27 or -1

I plotted, and there are two solutions.

ok then yes, Ireneoseaspe is right and Xishem as well. x=-27 and -1

Xishem, how to I plot and find solutions myself? Are you all using graphing calculators?

Ok, i take it back, no solutions. Viva wolfram

http://www.wolframalpha.com/input/?i=cos%5E-1++%28-1%29

who is wolfram?

If you put x = -1 you get 3 not 0

Aron: Show your work. I get 0 every time.

Xishem, do you know robby mayasich?

nvm, your profile pic reminded me of someone

http://www.wolframalpha.com/input/?i=%28-1%29%5E%281%2F3%29
Wolfram also thinks that is true. Weird.

And that error would explain why WolframAlpha doesn't give the correct answers.

(x^(1/3)+1) (x^(1/3)+3) = 0