What is the average rate of change of the function f(x)= X^2-4x+7 on the interval 1

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What is the average rate of change of the function f(x)= X^2-4x+7 on the interval 1

Mathematics
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basically its the slope formula: f(3) -f(1)/ 3-1
how did u get that?
find f(1) and f(3) average rate of change is \[m = [(f(3) - f(1)]/(3 - 1)\]

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Other answers:

rate of change = slope technically avg rate of change is defined as: \[\frac{1}{b-a}\int\limits_{a}^{b} f'(x) dx = \frac{f(b) -f(a)}{b-a}\]
so can i use m= Y2-Y1/X1-X2 ?
yep the avg slope in that interval is the same as the slope of the line connecting the 2 endpoints
0/2 ?
ok yeah thats it. 0/2 = 0 so the avg slope is 0
g(x)=mx+b, x1
Without doing any calculation, how can one determine the average rote of change of g(x)= mx+b over the interval X1
just plug it into the formula g(x2)-g(x1)/ x2-x1
and then ?
finish?
simplify, you should find that things cancel
mX2-mX1/X2-X1 ?
yep, now factor out the m
answer is m ?
yep :)
If f(x)=1/3^x and g(x)=x^3, what is the domain of (f.g)(x)?
(f into g)(x)
{x E R} ?
so you are plugging g(x) into the variable for f --> 1/3^g(x) = 1/3^(x^3) domain is all possible x_values
(f.g)(x) divided
f(x).g(x)
multiply
??
f(x) and g(x) are multiply
1/3^x * x^3
yeah
thats it
what is the domain?
oh, all real num there is no x value that makes it undefined
{x E R} ? x is not equal -1 ?
umm well R is used as notation for the set of all real numbers
i mean x can't be equal -1 or x can't be equal 0 or x can't be equal 1 or just { x E R } ?

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