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Solve for x I guess. You know how to do that, right? Then, you make a chart with the data...
all i did so far was find the derivative and replaced f(x) with 0
and found x= 0, 5, and -1
Ok. Those will be your interval points. They go: (infinity,o)(0,5) and (5,-1)
To find the y-int, sub in x=0
what do you mean?
|dw:1327657008314:dw| I mean that you make x=0 to for the y-intercept.
After you find the derivative equate it to 0 and solve for x, then substitute the 3 values you get into the given function. Now if it is negative,it has a max at that point and is therefore going to decrease in that interval whilst if it is positive it is a min and therefore it is going to increase in that interval.
I'd graph the curve find the zeros, x=0, 2 are the zeros.... found by factorising next find the 1st derivative..... and find the stationary points... next find the 2nd derivative and any possible points of inflexion.... test the 1st derivative points in the 2nd derivative to test concavity... draw the graphs... and read the intervals off...
i got it, thanks everyone
Good work everyone. BATMAN AWAY