The architect's side view drawing of a saltbox-style house shows a post that supports the roof ridge. The support posts is 10 ft tall. How far from the front of the house is the support post positioned? This is a triangle and this is the way or sample on how to do it: Corallary 2=x ab/ac= ac/ad
Corollary 1=y ad/cd= cd/db I was trying this to do the corollary 2: factor x/25 = 25/25x

- anonymous

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- dumbcow

how tall is the front of the house?

- anonymous

what i know is that the A to C is 25 ft

- anonymous

that is the base of the house

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## More answers

- dumbcow

|dw:1327657181669:dw|

- anonymous

how you write in the computer so i can do the drawing too so you can see it?

- dumbcow

below the textbox there is a "draw" button

- anonymous

: )

- dumbcow

to solve for x, we need either the angle the roof slopes or the length of the roof overhang

- anonymous

|dw:1327657374136:dw|

- anonymous

that help????

- dumbcow

yes :)

- dumbcow

where is front of house, A or C ?

- anonymous

c

- dumbcow

|dw:1327657781695:dw|
set up proportion using corresponding sides
x/10 = 10/(25-x)

- anonymous

is that all the answer, ok thanks

- dumbcow

well the goal is to solve for x....cross-multiply...set equal to 0

- anonymous

the point is that i am supposed to use the formular corollary1 and 2 to get the answer

- dumbcow

we are assuming triangle ABC is a right triangle ?

- anonymous

yes

- dumbcow

i used the corollary when setting up the proportion

- anonymous

I think i made a mistake it should be like this |dw:1327658765372:dw|

- dumbcow

|dw:1327658850698:dw|
congruent sides are always opposite congruent angles
put a's together and b's together
x/10 = 10/(25-x)

- dumbcow

oops i meant corresponding sides not congruent

- anonymous

yes that is exactly how i am doing ok could you continue please

- dumbcow

x(25-x) = 100
25x -x^2 = 100
x^2 - 25x +100 = 0
(x-20)(x-5) = 0
x= 20 or 5
x must be larger than 25-x according to diagram
x = 20

- anonymous

then i think should be x2

- anonymous

x should be from a to c

- dumbcow

correct

- dumbcow

oh that was from your 1st picture

- anonymous

yeap

- anonymous

so your answer is no correct?

- dumbcow

haha i'm not sure, so they want the length AC from your last pic?

- anonymous

the x is a to c

- anonymous

yes

- dumbcow

no the x i solved for was AD in first one, BD in 2nd one

- anonymous

and a to d

- anonymous

let me see

- dumbcow

|dw:1327659555813:dw|

- dumbcow

just use Pythagorean theorem to get AC

- anonymous

that is french haha

- dumbcow

no i think he was Greek. :)
right triangles....a^2 +b^2 = c^2

- anonymous

ok I have to go I really appreciate your help and patience : ) and of course the answer

- dumbcow

AC = 5sqrt(5)

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