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how tall is the front of the house?
what i know is that the A to C is 25 ft
that is the base of the house
how you write in the computer so i can do the drawing too so you can see it?
below the textbox there is a "draw" button
to solve for x, we need either the angle the roof slopes or the length of the roof overhang
where is front of house, A or C ?
|dw:1327657781695:dw| set up proportion using corresponding sides x/10 = 10/(25-x)
is that all the answer, ok thanks
well the goal is to solve for x....cross-multiply...set equal to 0
the point is that i am supposed to use the formular corollary1 and 2 to get the answer
we are assuming triangle ABC is a right triangle ?
i used the corollary when setting up the proportion
I think i made a mistake it should be like this |dw:1327658765372:dw|
|dw:1327658850698:dw| congruent sides are always opposite congruent angles put a's together and b's together x/10 = 10/(25-x)
oops i meant corresponding sides not congruent
yes that is exactly how i am doing ok could you continue please
x(25-x) = 100 25x -x^2 = 100 x^2 - 25x +100 = 0 (x-20)(x-5) = 0 x= 20 or 5 x must be larger than 25-x according to diagram x = 20
then i think should be x2
x should be from a to c
oh that was from your 1st picture
so your answer is no correct?
haha i'm not sure, so they want the length AC from your last pic?
the x is a to c
no the x i solved for was AD in first one, BD in 2nd one
and a to d
let me see
just use Pythagorean theorem to get AC
that is french haha
no i think he was Greek. :) right triangles....a^2 +b^2 = c^2
ok I have to go I really appreciate your help and patience : ) and of course the answer
AC = 5sqrt(5)