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anonymous

  • 4 years ago

Please help me in factoring this expression: 25a^2 - 9b^2 - c^2 + 6bc.

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  1. King
    • 4 years ago
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    (5a)^2-(3b-c)^2 =(5a+3b-c)(5a-3b+c)

  2. anonymous
    • 4 years ago
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    How did you get 3(b - c)^2?

  3. lalaly
    • 4 years ago
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    \[25a^2-(c^2-6bc+9b^2)\]\[25a^2-(c-3b)^2\]

  4. King
    • 4 years ago
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    no its 3b-c

  5. lalaly
    • 4 years ago
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    \[(5a+3b-c)(5a-3b+c)\]

  6. anonymous
    • 4 years ago
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    Is it 3b - c or c - 3b?

  7. King
    • 4 years ago
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    yeah i gave the same thing...pratu use a-b whole square formula.....3b-c

  8. lalaly
    • 4 years ago
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    he didnt factor out the minus sign like i did

  9. King
    • 4 years ago
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    i did

  10. lalaly
    • 4 years ago
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    so it doesnt matter, both work

  11. anonymous
    • 4 years ago
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    You both got the same answer.

  12. King
    • 4 years ago
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    why cant it be -(9b^2+c^2-6bc)?

  13. lalaly
    • 4 years ago
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    its the same:S

  14. anonymous
    • 4 years ago
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    Thanks lalaly and king.

  15. King
    • 4 years ago
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    kk!

  16. lalaly
    • 4 years ago
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    i showed u how i got it, so hope it helps

  17. King
    • 4 years ago
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    yeah actually (a-b)^2 is same as (b-a)^2

  18. anonymous
    • 4 years ago
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    It did help lalaly, thanks.

  19. lalaly
    • 4 years ago
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    :) anytime

  20. fj
    • 4 years ago
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    \[(5a)^{2}-(3b-c)^{2}\]

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