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AravindG
 4 years ago
wel i hav some doubts on trigonometruy wen i did revision can anyone help
AravindG
 4 years ago
wel i hav some doubts on trigonometruy wen i did revision can anyone help

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AravindG
 4 years ago
Best ResponseYou've already chosen the best response.4what is the formula for cos 2A *cos 4A *cos 8A ETC

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cos2A=1sinA i think..

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1cos 2A= cos^2 A sin ^2 A

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\cos^2A=1\sin^2A\] but it's not suqared

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no formula for this http://www.wolframalpha.com/input/?i=simplify+cos+2A+*cos+4A+*cos+8A

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1aravind do want the simplification of cos 2A* cos 4A * cos 8A

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.4no i think there is a formula

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.4somewat like sin 2^n alpha/(2^n sin alpha)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ah it doesn't end idk i haven't learn such formula in trig course

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you are from different country...

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.4:P but math is universal :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but we don't learn same things

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so as i said i didn't learn it in my trig course

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1aravind I'm trying to think, you're right that there is a formula, but i'm not able to recall

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.4oh thn next doubt u find it and post here later

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.4u knw solutions of triangles?

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1not very much but I'll try,

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.4in a triangle (a+b+c)(b+ca)=kbc if 0<k<4 prove

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1yeah aravind i'm thinking

Diyadiya
 4 years ago
Best ResponseYou've already chosen the best response.1\[Cos2x=\cos^2x\sin^2x\]

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1yeah, i can help with you second question equation 1....(a+b+c)(b+ca)= b^2+c^2a^2+2bc now we know cosine formula a^2=b^2+c^22bc*cos A so here b^2+c^2a^2=2bc cos A, subsitute this in equation 1 so 2bc cos A+ 2bc 2bc( cos A+1) now cos A 's max value is 1 and minimum 0 so the left side can be 0 or 4bc so k can vary from 0 to 4 0<k<4

vishal_kothari
 4 years ago
Best ResponseYou've already chosen the best response.6handbook of mathematics...

vishal_kothari
 4 years ago
Best ResponseYou've already chosen the best response.6it's not mine habit...
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