AravindG
  • AravindG
wel i hav some doubts on trigonometruy wen i did revision can anyone help
Mathematics
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
AravindG
  • AravindG
what is the formula for cos 2A *cos 4A *cos 8A ETC
anonymous
  • anonymous
cos2A=1-sinA i think..
anonymous
  • anonymous
no

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anonymous
  • anonymous
meant 1-sin2A
anonymous
  • anonymous
oh, no? ok
AravindG
  • AravindG
11+cos2a is 2sin^2A
ash2326
  • ash2326
cos 2A= cos^2 A- sin ^2 A
anonymous
  • anonymous
\[\cos^2A=1-\sin^2A\] but it's not suqared
AravindG
  • AravindG
.........
anonymous
  • anonymous
no formula for this http://www.wolframalpha.com/input/?i=simplify+cos+2A+*cos+4A+*cos+8A
ash2326
  • ash2326
aravind do want the simplification of cos 2A* cos 4A * cos 8A
ash2326
  • ash2326
*you
AravindG
  • AravindG
no i think there is a formula
AravindG
  • AravindG
for n terms
AravindG
  • AravindG
somewat like sin 2^n alpha/(2^n sin alpha)
anonymous
  • anonymous
ah it doesn't end idk i haven't learn such formula in trig course
AravindG
  • AravindG
its there tomas
anonymous
  • anonymous
you are from different country...
AravindG
  • AravindG
:P but math is universal :P
anonymous
  • anonymous
but we don't learn same things
anonymous
  • anonymous
so as i said i didn't learn it in my trig course
AravindG
  • AravindG
k
ash2326
  • ash2326
aravind I'm trying to think, you're right that there is a formula, but i'm not able to recall
AravindG
  • AravindG
oh thn next doubt u find it and post here later
AravindG
  • AravindG
u knw solutions of triangles?
ash2326
  • ash2326
not very much but I'll try,
AravindG
  • AravindG
:O
AravindG
  • AravindG
in a triangle (a+b+c)(b+c-a)=kbc if 0
AravindG
  • AravindG
??
AravindG
  • AravindG
ash
ash2326
  • ash2326
yeah aravind i'm thinking
Diyadiya
  • Diyadiya
\[Cos2x=1-2\sin^2x\]
Diyadiya
  • Diyadiya
\[Cos2x=\cos^2x-\sin^2x\]
Diyadiya
  • Diyadiya
\[Cos2x=2\cos^2x-1\]
ash2326
  • ash2326
yeah, i can help with you second question equation 1....(a+b+c)(b+c-a)= b^2+c^2-a^2+2bc now we know cosine formula a^2=b^2+c^2-2bc*cos A so here b^2+c^2-a^2=2bc cos A, subsitute this in equation 1 so 2bc cos A+ 2bc 2bc( cos A+1) now cos A 's max value is 1 and minimum 0 so the left side can be 0 or 4bc so k can vary from 0 to 4 0
AravindG
  • AravindG
wow perfect
vishal_kothari
  • vishal_kothari
http://www.mediafire.com/?t2tdkmznnzq
vishal_kothari
  • vishal_kothari
handbook of mathematics...
vishal_kothari
  • vishal_kothari
it's not mine habit...

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