anonymous
  • anonymous
a stone of mass 0.5kg tied with a string of length 1m is moving in a horizontal circle with speed 4m/s.the tension in the string is...
Physics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
|dw:1327670211788:dw| for vertical equilibrium
AravindG
  • AravindG
hey salini
AravindG
  • AravindG
heloo

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More answers

anonymous
  • anonymous
endha answer ariyo aravind?
AravindG
  • AravindG
maybe
AravindG
  • AravindG
tht answer to my qn was wnderful i was looking for tht
anonymous
  • anonymous
endha?
AravindG
  • AravindG
?
AravindG
  • AravindG
u gud in malayalam??
anonymous
  • anonymous
ene kurichu endha vijaricha ney?
AravindG
  • AravindG
enaal nallathu in this qn enikku thonunu tension is provided by the centripetal force
AravindG
  • AravindG
helo
anonymous
  • anonymous
annu pakshe e questionil angle kurichu onum thannela aa diagram yaane varachadhannu
AravindG
  • AravindG
y do u need angle for mv^2/r
anonymous
  • anonymous
|dw:1327671459182:dw|alla imagine chei if there was no angle then there wud be no force in the vertical direction to balance mg
AravindG
  • AravindG
http://www.twiddla.com/735087
JamesJ
  • JamesJ
The centripetal force, \( F_c \) required to keep the object in uniform circular motion is \[ F_c = \frac{mv^2}{r} \] |dw:1327674336876:dw| F_c is the force pointing towards the center of rotation. Now, where is that F_c provided from? It is provided but the tension, T, in the string. It is the component in F_c in that direction. The other piece of T is the vertical component and you know that must be equal to the weight of the mass, mg. If the string makes an angle theta to the vertical, we must have therefore that \[ T\cos\theta = mg \ \ \ \ -- (1) \] \[ T \sin\theta = F_c = \frac{mv^2}{r} \ \ \ \ -- (2) \] Now you know the length of the string, it is 1 m. And you know the radius of the rotation, it is \( r \). Hence another expression involving \( \theta \) is \[ \sin\theta = \frac{r}{1} = r \ \ \ \ -- (3) \] You now have enough equations to be able to solve for \( T \).
anonymous
  • anonymous
always ina horizontal circle there is some angle made with vertical or horizontal right?
JamesJ
  • JamesJ
By the string, yes.
AravindG
  • AravindG
:P
AravindG
  • AravindG
hey
AravindG
  • AravindG
u thr?

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