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anonymous
 4 years ago
ABCD is a square where A is the point (0,2) and C is the point (8,4). AC and BD are diagonals of the square and they intersect at E. Find the coordinates of B and D. Do you have any method other than using a vector
anonymous
 4 years ago
ABCD is a square where A is the point (0,2) and C is the point (8,4). AC and BD are diagonals of the square and they intersect at E. Find the coordinates of B and D. Do you have any method other than using a vector

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amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1yes, but its complicated :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0could you show me? thx alot!

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1since a square has diags that are perp to each other; we need 2 lines that meet in the middle of AC

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1the slope of a line is the important part here; once we know the slope of the line from A to C we can determine other things

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1the slope of a line is found by a slope formula:\[m=\frac{y1y2}{x1x2}\] but i tend to step it out. 1) subtract the points 2) stack y/x

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1C (8,4) A (0,2)  8,2; stack y/x: 2/8 = 1/4 for our slope

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1perp slopes have the habit of being the negative reciprocal of each other. m1*m2 = 1

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1perp slope for th eline from B to D is then: 4/1

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1we need a common point for these to meet at, which is the middle of the square and hence E the midpoint is just the average of 2 other points. Add the points and divide by 2 C (8,4) +A (0,2)  (8,6)/2 = (4,3) as out point for E

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1327673742761:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1this is what weve got drawn up in out heads, or on paper

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i know, this is where I had a brillant notion last time ... and I just remembered it :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1think of a pinwheel ....

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1327674432861:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1our x and y parts for A to E are going to be swapped and negated for the perp from B to E

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1327674563395:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1we know to go from A to E is over 4 and up 1 (x=4, y=1) these are the distances needed for the rest of them as well right? just perp them (x=1, y=4) is our directions from E to D (x=1, y=4) is our directions from E to B

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1E (4,3) E (4, 3) +(1,4) + (1,4)   B (3,7) D (5,1)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1that should clean up the right path a little better :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i kind of get it from the pinwheel ting

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1the pinwheel thing is a very good visual to guide us :)
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