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anonymous
 4 years ago
find x
anonymous
 4 years ago
find x

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0find x ^    here it is lol

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2we just found x yesterday

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2today we should find new and exciting things

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[(2x)^{\log_{2} }+(3x)^{\log_{3} }=0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0> x <

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2your logs have no arguemtns

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2is that spose to be: log2(2x) + log3(3x) = 0 by chance?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2so far youve written something thats just jibberish

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you need arguments after the logs, you have a typo

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i know log2(2x) + log3(3x) = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you guys are funny XD

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2ok, that I can do :) maybe log2(2)+log2(x)+log3(3)+log3(x) = 0 log2(x)+log3(x)= 2 hmmm

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you mean dw:1327678126892:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2change of base :) \[\frac{ln(x)}{ln(2)}+\frac{ln(x)}{ln(3)}=2\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2we would need a common denominator with this i assume

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2\[\frac{ln(3)ln(x)}{ln(3)ln(2)}+\frac{ln(2)ln(x)}{ln(2)ln(3)}=\frac{2}{ln(2)ln(3)}\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2equate the tops\[ln(3)ln(x)+ln(2)ln(x)=2\] factor out the ln(x) \[ln(x)(ln(3)+ln(2))=2\] divide off the not ln(x) \[ln(x)=\frac{2}{(ln(3)+ln(2))}\] and e both sides

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2\[x=exp(\frac{2}{ln(3)+ln(2)})\] and that is my gut effort

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2http://www.wolframalpha.com/input/?i=log_3%283x%29%2Blog_2%282x%29%3D0 forgot to include the "common denominator" in the top, but not bad

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2\[x=exp(2\frac{ln(2)ln(3)}{ln(3)+ln(2)})\]
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