A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 4 years ago

find x

  • This Question is Closed
  1. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    find x ^ | | | here it is lol

  2. amistre64
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    we just found x yesterday

  3. amistre64
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    today we should find new and exciting things

  4. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Equation?

  5. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[(2x)^{\log_{2} }+(3x)^{\log_{3} }=0\]

  6. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ------------------> x <-------------------------

  7. amistre64
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    exp are exp

  8. amistre64
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    your logs have no arguemtns

  9. amistre64
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    is that spose to be: log2(2x) + log3(3x) = 0 by chance?

  10. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    just solve it

  11. amistre64
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    just notate it ....

  12. amistre64
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    so far youve written something thats just jibberish

  13. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you need arguments after the logs, you have a typo

  14. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i know log2(2x) + log3(3x) = 0

  15. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you guys are funny XD

  16. amistre64
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    ok, that I can do :) maybe log2(2)+log2(x)+log3(3)+log3(x) = 0 log2(x)+log3(x)= -2 hmmm

  17. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Do you mean |dw:1327678126892:dw|

  18. amistre64
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    change of base :) \[\frac{ln(x)}{ln(2)}+\frac{ln(x)}{ln(3)}=-2\]

  19. amistre64
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    we would need a common denominator with this i assume

  20. amistre64
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \[\frac{ln(3)ln(x)}{ln(3)ln(2)}+\frac{ln(2)ln(x)}{ln(2)ln(3)}=\frac{-2}{ln(2)ln(3)}\]

  21. amistre64
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    equate the tops\[ln(3)ln(x)+ln(2)ln(x)=-2\] factor out the ln(x) \[ln(x)(ln(3)+ln(2))=-2\] divide off the not ln(x) \[ln(x)=-\frac{2}{(ln(3)+ln(2))}\] and e both sides

  22. amistre64
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \[x=exp(-\frac{2}{ln(3)+ln(2)})\] and that is my gut effort

  23. amistre64
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    http://www.wolframalpha.com/input/?i=log_3%283x%29%2Blog_2%282x%29%3D0 forgot to include the "common denominator" in the top, but not bad

  24. amistre64
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \[x=exp(-2\frac{ln(2)ln(3)}{ln(3)+ln(2)})\]

  25. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.