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anonymous

  • 4 years ago

will you please show me a graph -8, -11

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  1. anonymous
    • 4 years ago
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    u mean graph that coordinate?

  2. anonymous
    • 4 years ago
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    (-8, -11)?

  3. anonymous
    • 4 years ago
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    It is just a point 8 units left of the x/y axis, 11 units down

  4. anonymous
    • 4 years ago
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    yepp :) agreed with rickjbr!

  5. anonymous
    • 4 years ago
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    |dw:1327679050325:dw|

  6. anonymous
    • 4 years ago
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    I have to show each system by graphing. its y = 3x =3 y = x-3 The answer is -8, and -11. But what does the graph look like to this I need to show the arrows

  7. anonymous
    • 4 years ago
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    You plug in values for x and solve for y. Then you draw a line through two or more points. You only need 2 points to draw the line, however.

  8. anonymous
    • 4 years ago
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    Therefore, Rick what does the graph look like

  9. anonymous
    • 4 years ago
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    Why do you say y=3x=3?

  10. anonymous
    • 4 years ago
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    Is there one equation or more?

  11. anonymous
    • 4 years ago
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    What is the equation you are trying to graph?

  12. anonymous
    • 4 years ago
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    No its y=3x+13 Y=x-3 im sorry

  13. anonymous
    • 4 years ago
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    You need to graph two lines?

  14. anonymous
    • 4 years ago
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    i know but how

  15. anonymous
    • 4 years ago
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    For my anwer for my graph i got -8,-11

  16. anonymous
    • 4 years ago
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    You have equations in the form of y=mx+b m is the slope, b is the y-intercept, which is where the line will intersect the y axis

  17. anonymous
    • 4 years ago
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    ok and then i graph it right? what would that look like

  18. anonymous
    • 4 years ago
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    What you need to do is plug in two values for x for each equation, then draw a line through the points (x1, y1) and (x2, y2)

  19. anonymous
    • 4 years ago
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    ok can you show my i am really having troble with this

  20. anonymous
    • 4 years ago
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    so for y=3x+13, you can plug in 1 for x and 2 for x When you plug in 1, y will be 16. When you plug in 2, y will be 19. So plot two points (1,16) and (2,19) and draw a line through them

  21. anonymous
    • 4 years ago
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    Another way to do this is to only put in one point and then use the slope. In y=3x+13, the slope is 3/1 (the m in y=mx+b)

  22. anonymous
    • 4 years ago
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    ok thanks alot you really help!!!

  23. anonymous
    • 4 years ago
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    Then for every 1 unit you increase x, y will increase by 3 units.

  24. anonymous
    • 4 years ago
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    You're welcome

  25. anonymous
    • 4 years ago
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    Do you understand now?

  26. anonymous
    • 4 years ago
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    yep thanks : )

  27. anonymous
    • 4 years ago
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    Sure thing.

  28. anonymous
    • 4 years ago
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    well, wait - I draw the graph, it doesn't look right. What would yours look like

  29. anonymous
    • 4 years ago
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    I'll try to draw one for you y=3x+13

  30. anonymous
    • 4 years ago
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    Actually i'll draw y=x-3 so i don't have to draw so many hashes

  31. anonymous
    • 4 years ago
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    |dw:1327680173064:dw|

  32. anonymous
    • 4 years ago
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    You see how in y = x-3, the line intersects the y axis at (0,-3)? That's because in y=mx+b, b is the y intercept. The line will cross the y axis at the y intercept

  33. anonymous
    • 4 years ago
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    in y = x-3, b = -3

  34. anonymous
    • 4 years ago
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    the slope (m) is 1/1, so for every 1 unit increase in x, y increases only 1 unit as well

  35. anonymous
    • 4 years ago
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    Did your graph for y = x-3 look anything like that?

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