## anonymous 4 years ago THE VELOCITY of a particle is

1. anonymous

|dw:1327679298439:dw| the component of velocity v parallel to the vector in the form of a is

2. anonymous

|dw:1327679486945:dw|

3. ash2326

unit vector of (i+j+k)= $$(i+j+k)/\sqrt{3}$$ angle between velocity vector and the second vector let the second vector be x we know that dot product of two vectors a and b is a.b=|a||b|cos theta so v.x=|v||x|cos (theta) (6i+2j-2k)(i+j+k)= $$\sqrt{44}* \sqrt(3) \cos \theta$$ 6/$$\sqrt {132}=\cos \theta$$ magnitude of velocity vector in the direction of x let the new vector be y |y|=|v| cos theta |y|= $$\sqrt{44} *6/ \sqrt{132}$$ |y|=6/ $$\sqrt 3$$ vector y= |y| x/|x| y= 6/ $$\sqrt 3$$ *(i+j+k)/$$\sqrt 3$$ y=2i+2j+2k

4. anonymous

nice work ash2326.

5. anonymous

hey ash in this question we have to find a component of v parallel to a vector

6. ash2326

|dw:1327683618621:dw|yeah , i'll show you how i've done

7. ash2326

|dw:1327683675640:dw|

8. ash2326

y=|y|* unit vector of x unit vector of x= x/|x|