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anonymous

  • 4 years ago

THE VELOCITY of a particle is

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  1. anonymous
    • 4 years ago
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    |dw:1327679298439:dw| the component of velocity v parallel to the vector in the form of a is

  2. anonymous
    • 4 years ago
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    |dw:1327679486945:dw|

  3. ash2326
    • 4 years ago
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    unit vector of (i+j+k)= \((i+j+k)/\sqrt{3}\) angle between velocity vector and the second vector let the second vector be x we know that dot product of two vectors a and b is a.b=|a||b|cos theta so v.x=|v||x|cos (theta) (6i+2j-2k)(i+j+k)= \(\sqrt{44}* \sqrt(3) \cos \theta\) 6/\(\sqrt {132}=\cos \theta \) magnitude of velocity vector in the direction of x let the new vector be y |y|=|v| cos theta |y|= \( \sqrt{44} *6/ \sqrt{132}\) |y|=6/ \(\sqrt 3\) vector y= |y| x/|x| y= 6/ \(\sqrt 3\) *(i+j+k)/\(\sqrt 3\) y=2i+2j+2k

  4. Shayaan_Mustafa
    • 4 years ago
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    nice work ash2326.

  5. anonymous
    • 4 years ago
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    hey ash in this question we have to find a component of v parallel to a vector

  6. ash2326
    • 4 years ago
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    |dw:1327683618621:dw|yeah , i'll show you how i've done

  7. ash2326
    • 4 years ago
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    |dw:1327683675640:dw|

  8. ash2326
    • 4 years ago
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    y=|y|* unit vector of x unit vector of x= x/|x|

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