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anonymous

  • 4 years ago

find f(x) domain \[f(x)=\log _{x-3}(x ^{2}-1)/(x ^{2}-4)\]

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  1. amistre64
    • 4 years ago
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    a few issues that might influence domain are an x under the fraction the x in the base notation, dont think we can have log_0 and the x on the log argument itself; nothing 0 and under is good

  2. anonymous
    • 4 years ago
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    you mean \[x >3 \]

  3. anonymous
    • 4 years ago
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    ?

  4. amistre64
    • 4 years ago
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    well, lets start with the log argument part: x^2 - 1 <= 0 is bad x^2 <= 1 x <= -1 , or x >=1 would be offlimits

  5. amistre64
    • 4 years ago
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    so we are defined by just that to be between -1 and 1

  6. amistre64
    • 4 years ago
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    nothing in the interval makes the bottom look bad so lets try to see if theres anything in there that would make the base part go bad

  7. amistre64
    • 4 years ago
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    there might be some issue in a -base for SOME numbers

  8. amistre64
    • 4 years ago
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    for instance: log-2(8) = y 8 = (-2)^y is not defined

  9. amistre64
    • 4 years ago
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    http://xa.yimg.com/kq/groups/4750694/1645343743/name/Negative+Bases+for+Logs.pdf

  10. anonymous
    • 4 years ago
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    the domain is this \[(3,4)\cup(4,+\infty)\]

  11. anonymous
    • 4 years ago
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    amir.sat is right

  12. amistre64
    • 4 years ago
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    i messed up on my x^2 - 1 dint i :)

  13. anonymous
    • 4 years ago
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    tnx

  14. anonymous
    • 4 years ago
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    amir you defeated the 100level guy

  15. amistre64
    • 4 years ago
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    ive been defeated plenty of times ;)

  16. amistre64
    • 4 years ago
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    wolfram would have told me if I was wrong in the end im sure of it lol

  17. anonymous
    • 4 years ago
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    lol :)

  18. anonymous
    • 4 years ago
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    but i've done that with my self if you have a lot of time i'll show you

  19. anonymous
    • 4 years ago
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    amir don't you want to give a question MedaL

  20. anonymous
    • 4 years ago
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    oww yeah

  21. anonymous
    • 4 years ago
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    \[{((-3 + x) (-1 + x^2))/(-4 + x^2)} \]

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