anonymous
  • anonymous
Find the equation of a line containing the given point and having the given slope. (2,8), m=5/4 y=___x+___ I'm having problems with the fractions themselves.
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
Using the line-slope notation, we can say that \(\Large y = mx + c\). We have x, y and m, so can we work out c?
anonymous
  • anonymous
y=5/4x+11/2
anonymous
  • anonymous
I was going more for the concept than the answer, 14yamaka.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
c=y-mx
anonymous
  • anonymous
sorry :S
anonymous
  • anonymous
\[y-y_1 = m(x-x_1) \] if I remember from A-Levels lol. So we have \[y-8 = \frac{5}{4}(x-2)\] \[y = \frac{5}{4}x +8- \frac{10}{4}\] \[y=\frac{5}{4}x +\frac{11}{2}\]
anonymous
  • anonymous
Thanks, guys. Those pesky fractions. Looks like I am really going to have to brush up on my basics. :(
anonymous
  • anonymous
The derivation of the equation I quoted comes from the general fact that \[m = \frac{y_2-y_1}{x_2-x_1}\] which can be proved easily once one knows the definition of gradient (distance up divided by distance along). We let \[(x_2,y_2)\] be an arbitrary point, and in doing this we can find the gradient of ANY line via: \[m = \frac{y-y_1}{x-x_1}\] which we rearrange to get the equation I began my last answer to...

Looking for something else?

Not the answer you are looking for? Search for more explanations.