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A clock gains 2 minutes per day and another loses 3 minutes per day. Both the clocks are started on a correct time at a given instant. They will again show the correct time for an instant within

Mathematics
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(a) a week (b) a month (c) six months (d) one year
I tried this before but could not formulate the equation. hmmmm....
wait, is this a digital clock? like is it 12 hours or 24 hours we're going for?

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Other answers:

I think 12 hours clock
one of the easier ways would be is to multiply to figure out the total number of minutes there are in the 12 hours and divide it by 5.
Each day, the clocks have gain a 5-minute gap between each other, so how big does the gap have to be to become 12 hours :)
I would say... 720 minutes per 12 hours, so the 2 minutes clock will be accurate again in 720/2/2 days = 180 days, the -3 minutes clock in 720/3/2 = 120 days. LCM of 180 and 120 is 360, so once a year?
But it's late here so my ability to reason left hours ago =)
Yes once a year is the correct answer.
I think that is right......
Yes, it matches the answer key
Good way to set it up.
oooohhh ok:) its 1:25 in the morning here :S lol
Haha where are you 14yamaka? It's 12:25am here.
japan haha
As we are giving away our local time it's 9:55 PM here.
Where are you FSM?
and where are you Fool?
I think FFM is in India
I am from India and FSM is from Australia.
Ah tis but early for you FFM :-P I'm in Perth, Australia.
after 3600 days
3600 days = 10 years o.O
whoa, that's 10 years
Why the 2 minutes clock will be accurate again in 720/2/2 days?
2 minute clock after 1800 days 3 minute clock after 1200 days
Is it 1800 or 180?
1800
I've shown my reasoning above, I got 180 days. I don't know HOW it could be 1800 or 1200 days, can you elaborate amir.sat?
So...?

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