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anonymous
 4 years ago
Find x intercepts? y=3x^2+11x4. Do I solve for y then substitute?
anonymous
 4 years ago
Find x intercepts? y=3x^2+11x4. Do I solve for y then substitute?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Y=0 for x intercepts.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\min{y = 3 x^2+11 x4} = 169/12 at x = 11/6 \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.03x(x+4)(1(x+4)=3x1=0=1/3 and x+4=0=4 coming to: 1/3,4 is this right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and that the possible answer.

phi
 4 years ago
Best ResponseYou've already chosen the best response.0I assume you made a typo 3x1=0=1/3 and x+4=0=4 coming to: 1/3,4 is this right? because the answer is +1/3 (which you found, but then typed in 1/3) @142343 x= 11/6 is where the parabola reaches a minimum, but its yvalue at x= 11/6 is not zero. The question is asking for the 2 points where the parabola crosses the xaxis dw:1327686228729:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.03x^2+11x4=0 3x^2+12xx4=0 3x(x+4)(x+4)=0 (x+4)(3x1)=0 x=4, 1/3
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