anonymous 4 years ago Hexagon A is a regular hexagon. The total length of all the sides of the hexagon is 24 inches. Hexagon A is dilated about its center to create Hexagon B. The length of each side of Hexagon B is inches. By what factor was Hexagon A dilated to create Hexagon B? I think it would be C. A. 4/5 B. 5/6 C. 1 1/5 D. 2

1. anonymous

Am I correct?

2. Mertsj

Well. what is the length of the side of Hexagon B?

3. anonymous

4 4/5

4. Mertsj

4x=4 4/5

5. Mertsj

C

6. Mertsj

Yes. You are correct. I was thinking octagon at first then I reread the problem

7. anonymous

$\frac{4+(4/5)}{4}=\frac{6}{5}=1\frac{1}{5}$C.

8. anonymous

Thanks

9. anonymous

Isn't area of a hexagon = a^2 * ( 3 * sqrt(3) ) / 2, where a is the length of the hexagon. Since the length of the side increased from 4 to 4.8 so the area should increase by 1.44

10. Mertsj

yw

11. anonymous

1.44 = square of (1 1/5)

12. anonymous

The question does not refer to areas or area ratios. The second hexagon can be constructed knowing how much larger the original side length is. The perimeter is proportional to the increase in side length

13. anonymous

Ok, I see, to me dilated meant area, but I see your point. @robtobey