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anonymous
 4 years ago
Choose the missing step in the given solution to the inequality 2x  14 > 4  3x.
2x  14 > 4  3x
10 > 5x
2 < x
Answer
x  14 > 4
14 < 4  5x
x  14 < 4
14 > 4  5x
anonymous
 4 years ago
Choose the missing step in the given solution to the inequality 2x  14 > 4  3x. 2x  14 > 4  3x 10 > 5x 2 < x Answer x  14 > 4 14 < 4  5x x  14 < 4 14 > 4  5x

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Hero
 4 years ago
Best ResponseYou've already chosen the best response.2I don't know who would actually solve it in a way that would intentionally make negative numbers.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well to solve any equation you would first add or subtract the solitary number that's on the same side as the variable (x in this case) to get x on it's own. Then divide or multiply both sides by the number attached to the variable.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh, I skipped a part I just realized. You would first need to get all your vairables together on one side of the equation.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2If it were up to me, I would add 3x to both sides and add 14 to both sides to get 5x > 10 x > 2 but even if it were 1o > 5x I would still add 5x and add 10 to both sides to get 5x > 10 The point is, you don't have to end up dividing by a negative number to get the solution.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Also note: When you divide or multiply both sides of an inequality by a negative, your inequality flips. So < becomes > and > becomes <

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2PsychoTink, that's the exact point I was trying to discourage people from doing because it leads to confusion.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2just swap the sides of the 5x and 10 to make them both positive without having to divide by negative numbers

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I would have also Hero, I would have kept things positive, but this one we'd have to blame on whomever wrote the book or problem the person is asking about. It looks like a multiple choice question to find the missing bit, and the book decided to be weird and make it really difficult.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2No, what I'm saying is, even if you get to 1o > 5x The next step is to add 5x to both sides, then add 10 to both sides all in one step to get 5x > 10

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2You can actually just swap the sides immediately when you see a negative on the variable.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2For example if 2x > 4, immediately swap sides to get 4 > 2x

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2If you do it that way, you'll never have to worry about dividing inequalities by negative numbers.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You could, but that's the really hard way to do it. Why would you have even put the x on that side. You can see that it starts negative, and you're only going to make it more negative by subtracting the 2, instead you could add the 3 right off the top and never have a negative situation

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2It's not the hard way if you think about it. I did it in one single step. You just swap the sides 2x > 4 4 >2x 2 > x How is that the hard way?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, if you have to show all your work it would be the hard way when you could have avoided it from every happening.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2dw:1327690510831:dw Dividing by negatives then remembering to switch the signs is the reason why students get things wrong. The point is to get the answer correct.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2Who cares if you have to show all your work. If you do it that way, you'd never have to worry about getting it wrong because you "forgot to switch a sign after dividing by a negative".

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2By the way, the answer to the original question is 14 > 4  5x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I completely agree with you Hero, that's why I was saying to take notice of what it's going to do in the start when you first have to combine your x. Right there you can see if you'll have a negative x or not and can start the problem accordingly. Rather than having to put yourself in that situation later.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2Sometimes though, you can't avoid getting negatives. In that case, you can use my method.
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