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More information coming -

\[x = 3\tan ((\pi*y)/3)\]

From y = 0 to 1 |dw:1327692518967:dw|

the bounds is from 0 to 1 right? up the y axis

Yes, 0 to 1 up the Y axis.

Ahh, sec^2x - 1 I assume?

\[9\pi\int_{0}^{1} sec^2(\frac{\pi}{3}y)-1\ dy\]
yes

I forgot my trig identities! Ahhh

Probably u-sub, much more familiar with that.

u = pi/3 y
du/dy = pi/3
dy = du/(pi/3) = 3du/pi

same results, we need to include a 3/pi

now, do you want to go ahead with this? or do we dare change the limits to match u instead of y :)

yep, now the whole thing is speaking in us and not partial tongues lol

\[27(tan(60^o)-\frac{pi}{3})\cancel{-27(tan(0^0)-0)}^{(\ 0\ )}\]

practice practice practice; after a bit it starts to sink in and make sense :)

i started with the older textbooks out of the college libraries and learnt myself up til now

if im right about this:
\[Volume=27\sqrt{3}-9pi\]

Yep! We got it!
Oh, I'm doing a paid online Calculus II class.. don't have a choice.