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anonymous
 4 years ago
hey guys i need help solving this limit problem, i know the answer is .25 but i dont know how to show that algebraically i will upload the equation
anonymous
 4 years ago
hey guys i need help solving this limit problem, i know the answer is .25 but i dont know how to show that algebraically i will upload the equation

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh and i cant use hospitals rule

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.1multiply top and bottom by \[\sqrt{4+x^5}+2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0are you sure it is +x^5?

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.1the only sign change you need in the one in front of the 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well that leaves me with 0/0 which is indeterminate form which is bad

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.1\[(\sqrt{4+x^5}2)(\sqrt{4+x^5}+2)=4+x^54=x^5\] then cancel the \(x^5\) that is in the numerator and the denominator

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{x\to 0}\frac{\sqrt{4+x^5}2}{x^5}\] \[\lim_{x\to 0}\frac{\sqrt{4+x^5}2}{x^5}\frac{\sqrt{4+x^5}+2}{\sqrt{4+x^5}+2}\] \[\lim_{x\to 0}\frac{x^5}{x^5(\sqrt{4+x^5}+2)}\] \[\lim_{x\to 0}\frac{1}{\sqrt{4+x^5}+2}\] \[\lim_{x\to 0}\frac{1}{\sqrt{4}+2}=\frac{1}{4}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh ok makes i see now thanks
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