A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
divide
x^2+8x+15
_______________divided x^2+6x+9/4x^25x6
4x^2+23x+15
anonymous
 4 years ago
divide x^2+8x+15 _______________divided x^2+6x+9/4x^25x6 4x^2+23x+15

This Question is Closed

Rogue
 4 years ago
Best ResponseYou've already chosen the best response.1Reciprocate the second fraction and multiply the two fractions. Try to factor things out to make it simpler.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Factored mostly with ac grouping except x^2+6x+9 which is simply (x+a)^2

Rogue
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac {x ^{2} + 8x +25}{4x ^{2} + 23x +15} \div \frac {x^{2} + 6x + 9}{4x^{2}  5x 6}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01st denominator factored by grouping like so: (4x^2 + 20x + 3x + 15) = 4x(x+5)+3(x+5)=(x+5)(4x+3)

Rogue
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac {x ^{2} + 8x +25}{4x ^{2} + 23x +15} * \frac {4x^{2}  5x 6}{x^{2} + 6x + 9}\]

Rogue
 4 years ago
Best ResponseYou've already chosen the best response.1And then factor & simplify as Rick says.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02nd denominator like: 4x^28x+3x6=4x(x2)+3(x2)=(x2)(4x+3)

Rogue
 4 years ago
Best ResponseYou've already chosen the best response.1I typed the first quadratic wrong, was correcting it to 15, instead of 25.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Then its just a matter of cancelling out like factors
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.