anonymous
  • anonymous
divide x^2+8x+15 _______________divided x^2+6x+9/4x^2-5x-6 4x^2+23x+15
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Rogue
  • Rogue
Reciprocate the second fraction and multiply the two fractions. Try to factor things out to make it simpler.
anonymous
  • anonymous
(x-2)^2(4x+3)/(x+3)
anonymous
  • anonymous
Factored mostly with ac grouping except x^2+6x+9 which is simply (x+a)^2

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Rogue
  • Rogue
\[\frac {x ^{2} + 8x +25}{4x ^{2} + 23x +15} \div \frac {x^{2} + 6x + 9}{4x^{2} - 5x -6}\]
anonymous
  • anonymous
1st denominator factored by grouping like so: (4x^2 + 20x + 3x + 15) = 4x(x+5)+3(x+5)=(x+5)(4x+3)
Rogue
  • Rogue
\[\frac {x ^{2} + 8x +25}{4x ^{2} + 23x +15} * \frac {4x^{2} - 5x -6}{x^{2} + 6x + 9}\]
Rogue
  • Rogue
And then factor & simplify as Rick says.
anonymous
  • anonymous
2nd denominator like: 4x^2-8x+3x-6=4x(x-2)+3(x-2)=(x-2)(4x+3)
Rogue
  • Rogue
+15*
anonymous
  • anonymous
Sorry?
Rogue
  • Rogue
I typed the first quadratic wrong, was correcting it to 15, instead of 25.
anonymous
  • anonymous
ah ok
anonymous
  • anonymous
Then its just a matter of cancelling out like factors

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