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anonymous

  • 4 years ago

divide x^2+8x+15/4x^2+23x+15 divide x^2+6x+9/4x^2-5x-6

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  1. myininaya
    • 4 years ago
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    \[\frac{x^2+8x+15}{4x^2+23x+15} \cdot \frac{4x^2-5x-6}{x^2+6x+9}\] \[\frac{(x+5)(x+3)}{4x^2+20x+3x+15} \cdot \frac{(x-6)(x+1)}{(x+3)(x+3)}\]

  2. myininaya
    • 4 years ago
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    now i basically have done this problem for you i left some factoring for you in the denominator of the first fraction(hint factor by grouping) after that you will cancel some stuff

  3. anonymous
    • 4 years ago
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    i m not getting any where

  4. myininaya
    • 4 years ago
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    on the part I left you?

  5. myininaya
    • 4 years ago
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    do you know how to factor by grouping?

  6. myininaya
    • 4 years ago
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    \[4x^2+20x+3x+15=4x(x+5)+3(x+5)\] can you do it from here?

  7. myininaya
    • 4 years ago
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    just factor 4x(x+5)+3(x+5)

  8. myininaya
    • 4 years ago
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    and you will be done with the factoring part then you can cancel stuff

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