anonymous
  • anonymous
how do is solve this 13x^2-38x-3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Mertsj
  • Mertsj
Do you mean how to factor it?
anonymous
  • anonymous
yes
Mertsj
  • Mertsj
(13x+1)(x-3)

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anonymous
  • anonymous
how
Mertsj
  • Mertsj
Do you know that trinomials come from multiplying two binomials?
anonymous
  • anonymous
yes
Mertsj
  • Mertsj
So we know it would be ( )( )
anonymous
  • anonymous
yes i get that
Mertsj
  • Mertsj
We also know that one sign would have to be positive and one negative since the last term is negative. Still with me?
anonymous
  • anonymous
yes agree
Mertsj
  • Mertsj
Now how could we possibly get 13x^2 ?
anonymous
  • anonymous
what do u mean?
anonymous
  • anonymous
you can do this by grouping with the ac method: ax^2+bx+c a=13 c=-3 ac=-39x^2 Find two factors of -39 that add up to -38 The factors are -39x and +1x To group, rewrite the equation 13x^2-39x+1x-3 remove like variables 13x(x-3)+1(x-3) remove (x-3) as a factor and combine 13x+1: (x-3)(13x+1)
Mertsj
  • Mertsj
The first term of the trinomial we are trying to factor is 13x^2. So we have to multiply 2 factors that will give us 13x^2 . What might they be?
Mertsj
  • Mertsj
Oh. I see that rickjbr wants to help you now so I'll turn you over to him.
anonymous
  • anonymous
1*13
anonymous
  • anonymous
sorry mertsj
anonymous
  • anonymous
didn't mean to jump in
anonymous
  • anonymous
so who's going to help me?
anonymous
  • anonymous
i'll help
anonymous
  • anonymous
ok so i don't understand why it is (x-3)(13x+1)
anonymous
  • anonymous
if you expand those two binomials, youll get back to your original trinomial using the FOIL method
anonymous
  • anonymous
13x^2+1x-39x-3= 13x^2-38x-3
anonymous
  • anonymous
oh i got it i was just confusing myself
anonymous
  • anonymous
thank you!!!
anonymous
  • anonymous
sure no problem

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