anonymous
  • anonymous
what is the vertical and horizontal asymptote of (8x+1)/(4x-8) please show steps
Mathematics
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anonymous
  • anonymous
what is the vertical and horizontal asymptote of (8x+1)/(4x-8) please show steps
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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Hero
  • Hero
graph it
anonymous
  • anonymous
2 and 2 respectively. Refer to the attached plot.
1 Attachment
anonymous
  • anonymous
hey robtobey, thanks for the help. i have another question dealing with translation, can you help me please

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anonymous
  • anonymous
hey robtobey, is there a way i can mathematically solve this problem using steps. i dont own a graphing calculator and im going to have to perform a similar problem like this on a test
anonymous
  • anonymous
The horizontal comes from dividing the coefficient of x in the Numerator and the Denominator respectively. The vertical is derived by setting the Numerator to zero and solving for x.
anonymous
  • anonymous
ok ok thanks
anonymous
  • anonymous
i have this other question
anonymous
  • anonymous
Go ahead.
anonymous
  • anonymous
|dw:1327704241742:dw| if i translate this graph using y=-f(x+2)+1...what would it look like
anonymous
  • anonymous
This is just a wild guess. The curve would be shifted right 2 and up 1.
anonymous
  • anonymous
like this?
anonymous
  • anonymous
|dw:1327704763026:dw|
anonymous
  • anonymous
or this
anonymous
  • anonymous
|dw:1327704817793:dw|
anonymous
  • anonymous
"The vertical is derived by setting the Numerator to zero and solving for x." is incorrect. Numerator should be replaced by Denominator, to obtain x so that there is division by zero.
anonymous
  • anonymous
are you talking about the last question
anonymous
  • anonymous
No, the original, (8x+1)/(4x-8).
anonymous
  • anonymous
Sorry, I am going to bail on your last question. It would take too long to do a real time google research to offer a solution in timely manner.
TuringTest
  • TuringTest
...two left and up one to your last question

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