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asnaseer Group Title

How to align the equals signs on equations of the form: f(2) = 2*(2)^2 + 8 = 2*4 + 8 = 8 + 8 = 16

  • 2 years ago
  • 2 years ago

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  1. asnaseer Group Title
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    \[\]To achieve this you need to enclose your equations between \\([\)\\(\)begin{align} and \\(\)end{align}\\(]\). Each equal sign should be preceded with an '&' symbol, and each line should end with a double backslash (i.e. \\). So the sample equation in the question would be written out as: \\([\)\\(\)begin{align} f(2) &= 2*(2)^2 + 8\\ &= 2*4 + 8\\ &= 8 + 8\\ &= 16 \\(\)end{align}\\(]\) This will produce something like this:\[\begin{align} f(2) &= 2*(2)^2 + 8\\ &= 2*4 + 8\\ &= 8 + 8\\ &= 16 \end{align}\]

    • 2 years ago
  2. satellite73 Group Title
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    \[\begin{array} f(2) &= 2*(2)^2 + 8\\ &= 2*4 + 8\\ &= 8 + 8\\ &= 16 \end{array}\] just checking it works with "array" as well

    • 2 years ago
  3. Akshay_Budhkar Group Title
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    how did they write it?

    • 2 years ago
  4. myininaya Group Title
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    when asnaseer come back we should tackle him with the question

    • 2 years ago
  5. myininaya Group Title
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    oh

    • 2 years ago
  6. myininaya Group Title
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    this is it

    • 2 years ago
  7. myininaya Group Title
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    \begin{array} f(2) &= 2*(2)^2 + 8\\ &= 2*4 + 8\\ &= 8 + 8\\ &= 16 \end{array}

    • 2 years ago
  8. Akshay_Budhkar Group Title
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    ??

    • 2 years ago
  9. myininaya Group Title
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    you know you can copy that code

    • 2 years ago
  10. myininaya Group Title
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    right click it

    • 2 years ago
  11. Akshay_Budhkar Group Title
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    \[\begin{align} f(2) &= 2*(2)^2 + 8\\ &= 2*4 + 8\\ &= 8 + 8\\ &= 16 \end{align}\]

    • 2 years ago
  12. myininaya Group Title
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    yep

    • 2 years ago
  13. Akshay_Budhkar Group Title
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    no but i want it in the equation editor

    • 2 years ago
  14. myininaya Group Title
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    you can do it in the equation editor

    • 2 years ago
  15. Akshay_Budhkar Group Title
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    \[\[\begin{align} f(2) &= 2*(2)^2 + 8\\ &= 2*4 + 8\\ &= 8 + 8\\ &= 16 \end{align}\]\]

    • 2 years ago
  16. myininaya Group Title
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    \[\begin{array} new line \\ new line \\ new line \end{array}\]

    • 2 years ago
  17. myininaya Group Title
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    i did that in equation editor

    • 2 years ago
  18. myininaya Group Title
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    i did a new line you have to do \begin{array} \\ newline\\ newline \end{array}

    • 2 years ago
  19. myininaya Group Title
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    oop

    • 2 years ago
  20. Akshay_Budhkar Group Title
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    ? i mlost

    • 2 years ago
  21. Akshay_Budhkar Group Title
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    \[\newline \newline\]

    • 2 years ago
  22. myininaya Group Title
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    |dw:1327727286914:dw|

    • 2 years ago
  23. Akshay_Budhkar Group Title
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    \[\begin{array} &akshay & myin \end{array} \]

    • 2 years ago
  24. Akshay_Budhkar Group Title
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    :(

    • 2 years ago
  25. Akshay_Budhkar Group Title
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    what am i supposed to type in the equation editor?

    • 2 years ago
  26. myininaya Group Title
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    not &

    • 2 years ago
  27. myininaya Group Title
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    \\ .

    • 2 years ago
  28. myininaya Group Title
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    \[\begin{array} \\akshay \\ myin \end{array}\]

    • 2 years ago
  29. Akshay_Budhkar Group Title
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    \[\begin {array} \\akshay \\myin \end {array}\]

    • 2 years ago
  30. Akshay_Budhkar Group Title
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    cool!

    • 2 years ago
  31. myininaya Group Title
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    \[\begin{array} \\akshay \\ myin \\ :) \end{array} \]

    • 2 years ago
  32. waleed_kha Group Title
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    \[\begin{align} Thank &=you\\ &= Its gr8 \\&=\huge {For \cancel { Not }2 \cancel{forget} } \end{align}. \] its so cool ! ^_^

    • 2 years ago
  33. Mr.Math Group Title
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    TEST: \[\begin{array} x&=2+3\times 4 \\ &=2+12 \\ &=14 \end{array}\]

    • 2 years ago
  34. mkone Group Title
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    Il y a aussi l'environment eqnarray: begin{eqnarray} f(2) &=& 2*(2)^2 - 8\\ &= & 2*4 - 8\\ &=& 8 - 8 \\ &=& 0\end{eqnarray}, displays: \(\begin{eqnarray} f(2) &=& 2*(2)^2 - 8\\ &= & 2*4 - 8\\ &=& 8 - 8 \\ &=& 0\end{eqnarray} \) Which is very similar indeed, but I'm sure there are some small difference that helps perfectionists smile. Here another example: \(\begin{eqnarray} f(2) = 2*(2)^2 - 8\\ = 2*4 - 8\\ = 8 - 8 \\ = 0\end{eqnarray} \) begin{eqnarray} f(2) = 2*(2)^2 - 8\\ = 2*4 - 8\\ = 8 - 8 \\ = 0\end{eqnarray} and Pascal's triangle: \(\begin{eqnarray} &1\\ &1\ 1\\ &1\ 2\ 1 \\ &1\ 3\ 3\ 1 \\ & 1\ 4\ 6\ 4\ 1 \\ &1\ 5\ 10\ 10\ 5\ 1 \end{eqnarray} \) begin{eqnarray} &1\\ &1\ 1\\ &1\ 2\ 1 \\ &1\ 3\ 3\ 1 \\ & 1\ 4\ 6\ 4\ 1 \\ &1\ 5\ 10\ 10\ 5\ 1 \end{eqnarray}

    • 2 years ago
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