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anonymous

  • 4 years ago

given f(x)=6x+3 and g(x)= sqrt(x + 1) what is f of g equal to

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  1. anonymous
    • 4 years ago
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    please show all calculations

  2. anonymous
    • 4 years ago
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    just plug f(x) into g(x) here

  3. anonymous
    • 4 years ago
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    rather g(x) into f(x)

  4. anonymous
    • 4 years ago
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    |dw:1327707750271:dw|

  5. anonymous
    • 4 years ago
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    f(6sqrt(x+1)+3)

  6. anonymous
    • 4 years ago
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    why isnt the 6 in the square root

  7. anonymous
    • 4 years ago
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    because it's 6(x) so 6(g(x))

  8. anonymous
    • 4 years ago
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    hmmm

  9. anonymous
    • 4 years ago
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    i have been taught different

  10. anonymous
    • 4 years ago
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    i was thought you just substitute x

  11. anonymous
    • 4 years ago
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    you're substituting the whole function g(x) for x in f(x)

  12. anonymous
    • 4 years ago
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    *taught

  13. TuringTest
    • 4 years ago
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    f(x)=6x+3 g(x)= sqrt(x + 1) f(g(x))=6(g(x))+3=6(sqrt(x+1))+3

  14. anonymous
    • 4 years ago
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    ohhhhh i see

  15. anonymous
    • 4 years ago
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    i thought you were supposed to plug f into g

  16. TuringTest
    • 4 years ago
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    that would be g of f

  17. anonymous
    • 4 years ago
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    or g into f

  18. anonymous
    • 4 years ago
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    yeah i see

  19. TuringTest
    • 4 years ago
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    that is what we did put g(x) where x was

  20. anonymous
    • 4 years ago
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    if it wanted g of f of x, you'd substitute the other function

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spraguer (Moderator)
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