anonymous
  • anonymous
given f(x)=6x+3 and g(x)= sqrt(x + 1) what is f of g equal to
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
please show all calculations
anonymous
  • anonymous
just plug f(x) into g(x) here
anonymous
  • anonymous
rather g(x) into f(x)

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anonymous
  • anonymous
|dw:1327707750271:dw|
anonymous
  • anonymous
f(6sqrt(x+1)+3)
anonymous
  • anonymous
why isnt the 6 in the square root
anonymous
  • anonymous
because it's 6(x) so 6(g(x))
anonymous
  • anonymous
hmmm
anonymous
  • anonymous
i have been taught different
anonymous
  • anonymous
i was thought you just substitute x
anonymous
  • anonymous
you're substituting the whole function g(x) for x in f(x)
anonymous
  • anonymous
*taught
TuringTest
  • TuringTest
f(x)=6x+3 g(x)= sqrt(x + 1) f(g(x))=6(g(x))+3=6(sqrt(x+1))+3
anonymous
  • anonymous
ohhhhh i see
anonymous
  • anonymous
i thought you were supposed to plug f into g
TuringTest
  • TuringTest
that would be g of f
anonymous
  • anonymous
or g into f
anonymous
  • anonymous
yeah i see
TuringTest
  • TuringTest
that is what we did put g(x) where x was
anonymous
  • anonymous
if it wanted g of f of x, you'd substitute the other function

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