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anonymous
 4 years ago
find the limit of 3x^2+6x9/2x^22 as x approaches 1
anonymous
 4 years ago
find the limit of 3x^2+6x9/2x^22 as x approaches 1

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asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0You might find this site useful: http://archives.math.utk.edu/visual.calculus/1/limits.7/ It has good walkthrough tutorials on this topic.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you basically just need to brush up on factoring

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(a+b)^2=a^2+2ab+b^2, if you factor a 3 out of that numerator, you will have this situation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah how do i factor 9 to add up to 6

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0factor out a 3 first, it will make it much easier

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats a difference of 2 squares

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if you expanded that you'd get x^29

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.03,6,9 all have a common factor of 3 here

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you have to factor the 3 out of the whole numerator so that when you multiply it you get the original expression back

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what you just did will yield 3x^2 + 18x 27

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now factor the denominator

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0very much the same thing, guess which number you're pulling out?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(difference of 2 squares), i mentioned it a little bit ago

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hehe you just did it mistakenly earlier

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0remember you typed (x3)(x+3)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, now it's all factored. put it all together and cancel like terms

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok but could i have plug in 1 and get an answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0actually, you can further factor the numerator

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0right now you have the numerator at (x^2+2x3)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you could not have p lugged 1 into the original equation before factoring it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0look at the original denominator

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if you plugged a 1 in here, you'd get a divide by 0 error

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i see you will just get 0/0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so try factoring x^2+2x3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now everything is factored

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so when i cancel i get x+3/x+1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0don't forget about the 3 and 2 you factored out

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0at this point you can plug in 1 and you will not get a divide by 0 error

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0because you cancelled out the (x1)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0when i reduce i get 3/1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have another limit problem but its approaching infinity

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x^2 + 2x3/2x^22 as x approaches infinity, what is the limit

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now look at this numerator and denominator

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you already factored them in the last problem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0give me your factored equation for this problem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the denominator further factors out to (x1)(x+1)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what happened to x+3?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0my final looks like this (x+3)/(2x+1)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that's as far as you can factor it: (x+3)/[2(x+1)]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what's your thinking on that? just trying to see where you're going wrong

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh my mistake, i see what you were doing

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats not a big deal to expand the denominator to 2x+2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so youd have (x+3)/(2x+2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i thought you meant the whole equation factored out to that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if you have 2(x+1)...why not just foil (2)(x)=2x...2(1)=2...2x+2...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you can, but it's generally not necessary after you've already factored

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0plus if you do it too early you'll have to factor it again later

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so since i can't plug in infinity...what should i do

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now you have to think what would happen to f(x) is you kept plugging in very large numbers

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it would remain large

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0try plugging in 100 just to test it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well it might cut down...but at the end it would still be large

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0100+3/2(100+1)=103/202= .50

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok thanks for the help

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just understand why that's the answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0when you start using very large numbers, +3 in the numerator and the +2 in the denominator are pretty much meaningless

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0essentially its like graphing x/(2x)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks for the explanaition
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