## anonymous 4 years ago m^3/8(m^-1/4+9m) simplify

1. anonymous

$\frac{m^3}{8\left(\frac{m^{-1}}{4+9m}\right)} = \frac{m^3(4+9m)}{8m^{-1}} = \frac{m^4(4+9m)}{8}$

2. Mertsj

Why did you post this problem again? And again it is not clear what the problem is.