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anonymous
 4 years ago
f(x)with radical sign 0.5x5;f(20),f(16),f(12),f(14)
f(20)=
find domain of the function
anonymous
 4 years ago
f(x)with radical sign 0.5x5;f(20),f(16),f(12),f(14) f(20)= find domain of the function

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can any one solve this

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0If it is the domain is all the numbers that make .5x5 positive or 0

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0\[f(20)=\sqrt{.5(20)5}=\sqrt{5}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0\[f(16)=\sqrt{.5(16)5}=\sqrt{85}=\sqrt{3}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0\[f(12)=\sqrt{.5(12)5}=\sqrt{65}=\sqrt{1}=1\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0\[f(14)=\sqrt{.5(14)5}=\sqrt{75}=\sqrt{2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0type an integer or decimal rounded to the nearest tenth as needed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0f(20)=2.2 is the correct answer

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Do you have a calculator?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Then pick it up and type square root 5 and see if you don't get 2.2

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Now do the others in the same way.

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0What is the square root of 3?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0What about the square root of 2?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0So now you have all the answers.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so domain of f(x) is all real numbers x where ?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0You know, it would really be nice if, when you ask for help, and someone helps you that you would have the common courtesy to read what they wrote.
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