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anonymous

  • 4 years ago

f(x)with radical sign 0.5x-5;f(20),f(16),f(12),f(14) f(20)= find domain of the function

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  1. anonymous
    • 4 years ago
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    can any one solve this

  2. Mertsj
    • 4 years ago
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    \[f(x)=\sqrt{.5x-5}\]

  3. Mertsj
    • 4 years ago
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    Is that the function?

  4. Mertsj
    • 4 years ago
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    If it is the domain is all the numbers that make .5x-5 positive or 0

  5. Mertsj
    • 4 years ago
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    \[\frac{1}{2}x-5\ge0\]

  6. Mertsj
    • 4 years ago
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    \[x \ge10\]

  7. Mertsj
    • 4 years ago
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    That is the domain.

  8. Mertsj
    • 4 years ago
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    \[f(20)=\sqrt{.5(20)-5}=\sqrt{5}\]

  9. Mertsj
    • 4 years ago
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    \[f(16)=\sqrt{.5(16)-5}=\sqrt{8-5}=\sqrt{3}\]

  10. Mertsj
    • 4 years ago
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    \[f(12)=\sqrt{.5(12)-5}=\sqrt{6-5}=\sqrt{1}=1\]

  11. Mertsj
    • 4 years ago
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    \[f(14)=\sqrt{.5(14)-5}=\sqrt{7-5}=\sqrt{2}\]

  12. anonymous
    • 4 years ago
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    type an integer or decimal rounded to the nearest tenth as needed

  13. anonymous
    • 4 years ago
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    f(20)=2.2 is the correct answer

  14. Mertsj
    • 4 years ago
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    Do you have a calculator?

  15. anonymous
    • 4 years ago
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    yes

  16. Mertsj
    • 4 years ago
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    Then pick it up and type square root 5 and see if you don't get 2.2

  17. anonymous
    • 4 years ago
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    yes

  18. Mertsj
    • 4 years ago
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    Now do the others in the same way.

  19. Mertsj
    • 4 years ago
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    What is the square root of 3?

  20. anonymous
    • 4 years ago
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    1.7

  21. Mertsj
    • 4 years ago
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    What about the square root of 2?

  22. anonymous
    • 4 years ago
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    1.4

  23. Mertsj
    • 4 years ago
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    So now you have all the answers.

  24. anonymous
    • 4 years ago
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    so domain of f(x) is all real numbers x where ?

  25. Mertsj
    • 4 years ago
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    You know, it would really be nice if, when you ask for help, and someone helps you that you would have the common courtesy to read what they wrote.

  26. anonymous
    • 4 years ago
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    1 am with you

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