A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Need Help with Geometry and Ratio!!!!
anonymous
 4 years ago
Need Help with Geometry and Ratio!!!!

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0In the diagram, AX = 10, XB=5, AY=4 and YC=8. What is the ratio of the area of AXY to the area of ABC? Express your answer as a common fraction.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327715430695:dw

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.0Are the triangles given to be similar? If so, what is the correspondence of vertices? Would you check to determine if the diagram is correctly labeled? Thanks.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The diagram (seems) not correct.

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.0I agree. I think that the SAS Similarity Theorem is needed for solution but the given data doesn't satisfy the theorem's hypothesis. Triangles are similar if two sides in one triangle are in the same proportion to the corresponding sides in the other, and the included angles are equal.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this is all the given information

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I could draw the diagram again to clarify.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327717724546:dw

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.0Are both the black segments of length h? It seems that they would differ in length. And, are the segments labeled h perpendicular to segment AB?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How come the black segments be equal in length? or am I misunderstanding ?!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah sorry, they don't have the same length and i believe they are perpendicular. That was the hint from my teacher.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327720461436:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0are you sure that this are the only given?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think it has something to do with ratio

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have here only assumptions. .

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the area of ACBAyx= area of CyxB the area of ACBCyxB= area of Ayx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, but how do I find the area?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this is what I've got 4/12 = p/h 4h/12=p dw:1327722363321:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but i am not sure how to find ABC.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0your problem is ABC? find area of ACB: sinA=h/(8+4) therefor h=12sinA area = 1/2bh = 1/2(10+5)(12sinA) ; substitute the value of h in the formula = 1/2(15)(12sinA) therefor: the area of ACB is 90sinA

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Can you clarify sinA?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no it,s not (8+4) for h, it's 10+5 , and (10+5) is 8+4, but anyway the answer is still 90 sinA

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sin A will be find if there's a given measure for the angle. .
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.