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anonymous
 4 years ago
Find the equation of a circle with centre (0,0) that passes through (8,15)
anonymous
 4 years ago
Find the equation of a circle with centre (0,0) that passes through (8,15)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x^2 + y ^2 = r ^2 (substitute the values :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can yu show me plug in the values

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[x^2 + y ^2 = r ^2\] the length of the radius of the circle is \[r=\sqrt{(8)^2+(15)^2} = 17\] \[x^2+y^2=289\] < is the equation of the circle

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol fine . (8)^2 + (15)^2 = r^2 64 + 225 = r ^2 289 = r^2 13 = r

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0where did yu get 17 from

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol kay hes right its 17

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0he took the square root of 17

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeh, just look at the answer up there and you will know where the 17 came from, it is the magnitued of the radius, whenever you want to find the magnited of a vector lets say (2,3), it is equal to the square root of the x, y values square. take a look at this: http://www.mathsisfun.com/algebra/circleequations.html

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0), it is equal to the square root of the x, y values SQUARED**
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