anonymous
  • anonymous
Find the equation of a circle with centre (0,0) that passes through (8,-15)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
x^2 + y ^2 = r ^2 (substitute the values :D
anonymous
  • anonymous
can yu show me plug in the values
anonymous
  • anonymous
\[x^2 + y ^2 = r ^2\] the length of the radius of the circle is \[r=\sqrt{(8)^2+(-15)^2} = 17\] \[x^2+y^2=289\] <-- is the equation of the circle

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anonymous
  • anonymous
lol fine -.- (8)^2 + (-15)^2 = r^2 64 + 225 = r ^2 289 = r^2 13 = r
anonymous
  • anonymous
where did yu get 17 from
anonymous
  • anonymous
its 13 not 17
anonymous
  • anonymous
nvm its 17
anonymous
  • anonymous
how do yu kno
anonymous
  • anonymous
lol kay hes right its 17
anonymous
  • anonymous
he took the square root of 17
anonymous
  • anonymous
i mean 289
anonymous
  • anonymous
yeh, just look at the answer up there and you will know where the 17 came from, it is the magnitued of the radius, whenever you want to find the magnited of a vector lets say (2,3), it is equal to the square root of the x, y values square. take a look at this: http://www.mathsisfun.com/algebra/circle-equations.html
anonymous
  • anonymous
), it is equal to the square root of the x, y values SQUARED**

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