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anonymous

  • 4 years ago

In a population of gerbils, long hair (H) is completely dominant over short hair (h). If 18% of the population has short hair, calculate the percentage of the population that is expected to be heterozygous (Hh).

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  1. anonymous
    • 4 years ago
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    long hair = P Short hair = q using the Hardy-Weinberg equation for genotypic frequencies \[p ^{2}+2pq+q ^{2}=1\] First use the equation to solve for the known value 18% hh \[.18 = q ^{2}\] \[\sqrt{.18}=q\] so q =.42 plug this allelic frequency into p+q = 1 which will give you the frequency of dominant alleles 1-.42 = p so p = .58 then just plug the p and q values found into the portion of the equation for heterozygous offspring. 2 (.58)(.42) which comes out to about .49 or 49% the entire population should be 33% homozygous dominant 49% heterozygous and 18% homozygous recessive Assuming I did the math right you may want to double check me.

  2. anonymous
    • 4 years ago
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    thank you that helped a lot :)

  3. anonymous
    • 4 years ago
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    Glad I could help! Thanks for the medal :)

  4. anonymous
    • 2 years ago
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    that was right? @andrea95

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