## anonymous 4 years ago In a population of gerbils, long hair (H) is completely dominant over short hair (h). If 18% of the population has short hair, calculate the percentage of the population that is expected to be heterozygous (Hh).

1. anonymous

long hair = P Short hair = q using the Hardy-Weinberg equation for genotypic frequencies $p ^{2}+2pq+q ^{2}=1$ First use the equation to solve for the known value 18% hh $.18 = q ^{2}$ $\sqrt{.18}=q$ so q =.42 plug this allelic frequency into p+q = 1 which will give you the frequency of dominant alleles 1-.42 = p so p = .58 then just plug the p and q values found into the portion of the equation for heterozygous offspring. 2 (.58)(.42) which comes out to about .49 or 49% the entire population should be 33% homozygous dominant 49% heterozygous and 18% homozygous recessive Assuming I did the math right you may want to double check me.

2. anonymous

thank you that helped a lot :)

3. anonymous

Glad I could help! Thanks for the medal :)

4. anonymous

that was right? @andrea95