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anonymous
 4 years ago
In a population of gerbils, long hair (H) is completely dominant over short hair (h). If 18% of the population has short hair, calculate the percentage of the population that is expected to be heterozygous (Hh).
anonymous
 4 years ago
In a population of gerbils, long hair (H) is completely dominant over short hair (h). If 18% of the population has short hair, calculate the percentage of the population that is expected to be heterozygous (Hh).

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0long hair = P Short hair = q using the HardyWeinberg equation for genotypic frequencies \[p ^{2}+2pq+q ^{2}=1\] First use the equation to solve for the known value 18% hh \[.18 = q ^{2}\] \[\sqrt{.18}=q\] so q =.42 plug this allelic frequency into p+q = 1 which will give you the frequency of dominant alleles 1.42 = p so p = .58 then just plug the p and q values found into the portion of the equation for heterozygous offspring. 2 (.58)(.42) which comes out to about .49 or 49% the entire population should be 33% homozygous dominant 49% heterozygous and 18% homozygous recessive Assuming I did the math right you may want to double check me.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you that helped a lot :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Glad I could help! Thanks for the medal :)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0that was right? @andrea95
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