anonymous
  • anonymous
Find the shortest distance from the line 2x+6y=3 and passing through the point (9,-7)
Mathematics
chestercat
  • chestercat
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Mertsj
  • Mertsj
That would be the perpendicular distance so you must first find the equation of the perpendicular through( 9,-7) that has slope 3.
Mertsj
  • Mertsj
Do that and we'll go from there.
anonymous
  • anonymous
can yu show me how to do it?

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anonymous
  • anonymous
If memory serves, \(\huge \frac{ 2(9)+6(-7)-3 } { \pm \sqrt{2^2+6^2 } }\)
Mertsj
  • Mertsj
Can you find the equation of a line whose slope is 3 and contains the point (9,-7)?
Mertsj
  • Mertsj
Oh. I see that Fool wants to help you now so I'll turn you over to him.
anonymous
  • anonymous
lol yu can still help me
anonymous
  • anonymous
im not sure if yur suppose to use the quadratic formula for this
Mimi_x3
  • Mimi_x3
THe formula for this, i think: \[\large \frac{ax_{1}+by_{1}+c}{\sqrt{a^{2}+b^{2}}} \]
anonymous
  • anonymous
there is a formula for it
anonymous
  • anonymous
The proof requires representing the lines in normal form and then finding the perpendicular distances.
anonymous
  • anonymous
Mimi, your formula is close but not apt, it should be Either, \[ \large \pm\frac{ax_{1}+by_{1}+c}{\sqrt{a^{2}+b^{2}}} \] or \[ \large \frac{|ax_{1}+by_{1}+c|}{\sqrt{a^{2}+b^{2}}} \] Recall, Euclidean distance cannot be negative :)
Mimi_x3
  • Mimi_x3
lol, yeah i forgot my bad.
anonymous
  • anonymous
no worries, as long as you give me medal :P
Mimi_x3
  • Mimi_x3
obssessed of medals huh :P
anonymous
  • anonymous
whats the point of medals? do yu get nythin
anonymous
  • anonymous
hehe, not really it's fun though.
Mimi_x3
  • Mimi_x3
You get nothing, just a level, it just a waste of time anyway :P
anonymous
  • anonymous
Why should I answer you? Will I get anything? What is the purpose of anything in life? Life is as meaningless itself as this discussion :P
anonymous
  • anonymous
LMAO ^
Mimi_x3
  • Mimi_x3
Lol, life is cruel.
anonymous
  • anonymous
;)

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