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  • 4 years ago

An elevator starts from rest with a constant upward acceleration and moves 1 m in the first 1.8 s. A passenger in the elevator is holding a 8.7 kg bundle at the end of a vertical cord. What is the tension in the cord as the elevator accelerates? The acceleration of gravity is 9.8 m/s^2 Answer in units of N

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  1. TuringTest
    • 4 years ago
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    Over the first meter we can find the acceleration of the elevator\[x=\frac1 2at^2\]Where x and t are given in the problem. The tension force on the string will be equal to the force of gravity, plus the force due to the acceleration of the elevator.\[ T=F_g+F_E=mg+ma\]

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