## anonymous 4 years ago An elevator starts from rest with a constant upward acceleration and moves 1 m in the ﬁrst 1.8 s. A passenger in the elevator is holding a 8.7 kg bundle at the end of a vertical cord. What is the tension in the cord as the elevator accelerates? The acceleration of gravity is 9.8 m/s^2 Answer in units of N

Over the first meter we can find the acceleration of the elevator$x=\frac1 2at^2$Where x and t are given in the problem. The tension force on the string will be equal to the force of gravity, plus the force due to the acceleration of the elevator.$T=F_g+F_E=mg+ma$