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anonymous
 4 years ago
simplify i^6 times i^8
anonymous
 4 years ago
simplify i^6 times i^8

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but, is i a variable or complex number?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if its a variable, leave it as i^14

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.1\[i^{6+8}=i^{14}=i^{4n+2}=1\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0where did the i go? and where did the 4n+2 come from?

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.114= 4 (3) +2 which is of the form 4n +2

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.1is "i" complex number?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait, ofree, answer the question

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is i a complex number?

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.1or is it a variable?

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.1\[x^a \times x^b= x^{a+b}\] Remember that.. i believe it is a variable

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.1so your answer is \[i^{14}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What Akshay is doing is showing you how to figure out the system of complex numbers. the root of 1 is called i. Therefore, i^2=1 and i^4 is 1. 4n+2 refers to this pattern for complex numbers.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the only options are i, 1, i, 1 so i^14 is not the answer
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