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anonymous

  • 4 years ago

simplify i^6 times i^8

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  1. anonymous
    • 4 years ago
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    (i^6)(i^8) =i^14 =-1

  2. anonymous
    • 4 years ago
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    but, is i a variable or complex number?

  3. anonymous
    • 4 years ago
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    if its a variable, leave it as i^14

  4. Akshay_Budhkar
    • 4 years ago
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    \[i^{6+8}=i^{14}=i^{4n+2}=-1\]

  5. anonymous
    • 4 years ago
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    where did the i go? and where did the 4n+2 come from?

  6. Akshay_Budhkar
    • 4 years ago
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    14= 4 (3) +2 which is of the form 4n +2

  7. Akshay_Budhkar
    • 4 years ago
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    is "i" complex number?

  8. anonymous
    • 4 years ago
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    wait, ofree, answer the question

  9. anonymous
    • 4 years ago
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    Is i a complex number?

  10. Akshay_Budhkar
    • 4 years ago
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    or is it a variable?

  11. Akshay_Budhkar
    • 4 years ago
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    \[x^a \times x^b= x^{a+b}\] Remember that.. i believe it is a variable

  12. Akshay_Budhkar
    • 4 years ago
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    so your answer is \[i^{14}\]

  13. anonymous
    • 4 years ago
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    What Akshay is doing is showing you how to figure out the system of complex numbers. the root of -1 is called i. Therefore, i^2=-1 and i^4 is 1. 4n+2 refers to this pattern for complex numbers.

  14. anonymous
    • 4 years ago
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    the only options are i, -1, -i, 1 so i^14 is not the answer

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