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anonymous
 4 years ago
integrate[sec^3x]
anonymous
 4 years ago
integrate[sec^3x]

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{?}^{?}\sec ^{3}\theta d \theta\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327731874453:dwdw:1327732061041:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0because the reciprocal ratio for sec is 1/cosx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so then just bring the power to the front

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks, never thought about that move;

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327732192064:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0also have to know the general power rule wich is

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327732252138:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im not getting the rule.. explain?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.3no that won't quite work above you are going to integration by parts I think here

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it was solved, but idk y he squared the last integral and the power rule he stated

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.3u=secx du=secxtanx dv=sec^2x u=tanx

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.3\[\int \sec^3xdx=\sec x \tan x\int \sec x\tan^2xdx\]\[=\sec x \tan x\int \sec x(1\sec^2x)dx\]\[=\sec x \tan x\int\sec^3 xdx+\int\sec xdx\]have it from there ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, got it; thanks, for the integral of secx, you change to 1/cosx, then multiply by cosx/cos right?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.3\[\int\sec xdx=\int\sec x(\frac{\sec x+\tan x}{\sec x+\tan x})=\int\frac{du}{u}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i c, kk thanks alot man =)
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