## anonymous 4 years ago A sports car moving at constant speed travels 110m in 5.0 seconds. If it then brakes and comes to a stop in 4.0 seconds, what is the acceleration in m/s^2? Express the answer in terms of "g's", where 1.00g=9.80m/s^2 The answers are -5.5m/s^2 and -0.56g's

find the cars initial speed; the distance it covers in an amount of time, which is given at the beginning$v_i=\frac d t=\frac{110}{5}$then the formula for acceleration which is$a=\frac{v_f-v_i}{t}$where t in this equation is the time needed to stop, and the final velocity is zero.$a=\frac{0-22}{4}$divide this by 9.8 to get this in terms of g's