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|dw:1327757617642:dw|

james why arent u bringing tension oor gravity into the poicture?

when we equate the velocity and acceleration*

wndful

And I also had yet another typo, sorry....
\[\omega^2 = \frac{v^2}{r^2} \text{ not } v^2r^2\]
:)

i hav a doubt

u see in eqns of moment of inertia like mr^2,mr^2/2

what is the r basically??

total energy is k.e+p.e right so y arent u guys including that anywhere ?

|dw:1327769992982:dw|

|dw:1327770030252:dw|

i rotate about axis q then r is??

|dw:1327770065239:dw|

change in kinetic energy=work done by net force=m*a

hey actually i did that qn

no. m*a is not the work done. It is the force.

pls tell the sides are made of rods

in ther question they have asked for a in terms of M,m.g but we have to include displacement here

wat is momentr of inertia?

And no we don't, not for the acceleration.

hey but salini gave me the answr 3mr^2

when?

hey we did that remember?

is athat an equilateral triangle?

ys

made of uniform rods of length l

q is centre of mass

then use trignometry to find aq

axis is q

aq is l/root 3 then??

3*m*(aq)^2

that is 3 ml^2

srry ml^2

annu

u gud in maths?

salini?

arayila enniku orakam verunu anywaY PARA NOOKATE

http://www.twiddla.com/736142

siddhantsharan, why is Tr = Mr^2 / 2 * a / 2r
that is I*a/2r why? and how?

Sorry. Typo error. Answer is still the same.

YOu got the concept right?

Tr = Mr^2 / 2 * a / 2r
here, is a/2r the angular acceleration of cylinder if so T=M*a*r/4 not Ma/4

Wait I'll draw it for clarity.|dw:1327878291024:dw|

last doubt.....how did u get T*r ?