AravindG
  • AravindG
a sphere of mass m is attached to a spring and placed on an inclined plane as shown in fig .If a sphere is left free what is maximum extension of the spring if friction allows only rolling of sphere about a horizontal diameter
Physics
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SOLVED
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katieb
  • katieb
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AravindG
  • AravindG
|dw:1327758612150:dw|
anonymous
  • anonymous
u mean no friction?
anonymous
  • anonymous
if so, F = g/sin theta

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JamesJ
  • JamesJ
What exactly is the question?
anonymous
  • anonymous
|dw:1327765928827:dw| mgsin@ is the net force*x=1/2kx^2|dw:1327765781010:dw|
AravindG
  • AravindG
salini right side not clear
anonymous
  • anonymous
|dw:1327709932298:dw| Let Initial height be h. Two methods 1) The longer one with forces. At any instant, ma = mgsin@ - kx - f And Torque, fr = (2/5 m r ^2) * a/r => f = 2/5ma 7/5 m vdv/dx = mgsin@ - kx Integrating from initial v = 0 to finally when again v = 0 for max extension and x (displacement and extension) from 0 to x max , => x = (2mgsin@/k) ^1/2 Or you can simply obtain this expression frrom energy conservation. As change in Gravitational P.E. = Gain in Spring P.E mgxsin@ = 1/2kx^2 Only to get same answer. Just remember that mac extension is not the point at which forces are balanced because at that instant the body possess velocity hence goes further down only to perform SHM - you could have solved it using that concept too to find the amplitude.
anonymous
  • anonymous
Is that correct?
anonymous
  • anonymous
And I assumed it to be a solid sphere. hence Moment of inertia was 2/5 mr^2

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