a sphere of mass m is attached to a spring and placed on an inclined plane as shown in fig .If a sphere is left free what is maximum extension of the spring if friction allows only rolling of sphere about a horizontal diameter
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Not the answer you are looking for? Search for more explanations.
What exactly is the question?
mgsin@ is the net force*x=1/2kx^2|dw:1327765781010:dw|
salini right side not clear
|dw:1327709932298:dw| Let Initial height be h.
1) The longer one with forces.
At any instant,
ma = mgsin@ - kx - f
fr = (2/5 m r ^2) * a/r
=> f = 2/5ma
7/5 m vdv/dx = mgsin@ - kx
Integrating from initial v = 0 to finally when again v = 0 for max extension and x (displacement and extension) from 0 to x max ,
=> x = (2mgsin@/k) ^1/2
Or you can simply obtain this expression frrom energy conservation.
As change in Gravitational P.E. = Gain in Spring P.E
mgxsin@ = 1/2kx^2
Only to get same answer.
Just remember that mac extension is not the point at which forces are balanced because at that instant the body possess velocity hence goes further down only to perform SHM - you could have solved it using that concept too to find the amplitude.
Is that correct?
And I assumed it to be a solid sphere. hence Moment of inertia was 2/5 mr^2