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elica85
Group Title
What is the magnitude of the force on the 10 charge in the figure ?
 2 years ago
 2 years ago
elica85 Group Title
What is the magnitude of the force on the 10 charge in the figure ?
 2 years ago
 2 years ago

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elica85 Group TitleBest ResponseYou've already chosen the best response.1
dw:1327758982728:dw
 2 years ago

elica85 Group TitleBest ResponseYou've already chosen the best response.1
the resultant force should be...dw:1327759214456:dw something like that
 2 years ago

elica85 Group TitleBest ResponseYou've already chosen the best response.1
broke down x and y components for force on + on  and  on  and then added...not getting right answer
 2 years ago

fryad_muhammed Group TitleBest ResponseYou've already chosen the best response.0
450*10^9 N
 2 years ago

elica85 Group TitleBest ResponseYou've already chosen the best response.1
can you explain?
 2 years ago

elica85 Group TitleBest ResponseYou've already chosen the best response.1
it's not the right answer
 2 years ago

fryad_muhammed Group TitleBest ResponseYou've already chosen the best response.0
why?
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
it is not easy. it is a vector quantity. therefore you must have to consider directions.
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
you have to wait until i solve it for you. ok elicia85?
 2 years ago

elica85 Group TitleBest ResponseYou've already chosen the best response.1
sure and can you please show steps??
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
yes i will show steps to you. wait. i am here.
 2 years ago

elica85 Group TitleBest ResponseYou've already chosen the best response.1
ok thank you
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
you are welcome.
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
here is diagram first look at this and understand this.
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
is this pic making sense to you? if i do anything wrong here then kindly point out me. you too faryad, hei, elicia85 and an unknown person.
 2 years ago

fryad_muhammed Group TitleBest ResponseYou've already chosen the best response.0
thank you Shayan
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
wait i have to go and just come in 2min
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
hello. it is taking too much time for me. lets solve step by step here. ok. force of +15nC will be represented by F15 force of 10nC will be represented by F10 force of 5nC will be represented by F5 ok.
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
now as you can see. on 10nC there are two forces acting on it. 1)F15 which is attractive and at an angle of 45 2)F5 which repulsive.
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
F15 can be resolve into factors. along xaxis and along yaxis.
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
forces along yaxis can be calculated as, F15y=(kq1q2)/r² sin45 and F5y=(kq1q2)/r² forces along xaxis can be calculated as, F15x=(kq1q2)/r² cos45
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
finally. sum forces and you will get your answer.
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
have you got it? it is done.
 2 years ago

elica85 Group TitleBest ResponseYou've already chosen the best response.1
it's exactly what i did but i will try again
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
can you show your solution?
 2 years ago

elica85 Group TitleBest ResponseYou've already chosen the best response.1
well you still have to add the F5 on F10 don't you? which will only consist of y direction force
 2 years ago

elica85 Group TitleBest ResponseYou've already chosen the best response.1
my answer was 4.07*10^3
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
well you still have to add the F5 on F10 don't you? which will only consist of y direction force on yaxis: F10y=F15sin45  F5 on xaxis: F10x= F15x finally, \[F _{10}=\sqrt{(F _{10y})^{2}+(F _{10x})^{2}}\] This is complete.
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
any question?
 2 years ago

fryad_muhammed Group TitleBest ResponseYou've already chosen the best response.0
shayan can you help me?
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
of course fryad. although we are brothers. arn't we?
 2 years ago

elica85 Group TitleBest ResponseYou've already chosen the best response.1
thank you i'll try again!
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
you are ever welcome. Regards, Read my Profile. :D
 2 years ago

fryad_muhammed Group TitleBest ResponseYou've already chosen the best response.0
yes ,sure thank you , please prove this for me A.B=cos& A.B
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
ok w8. let me analyze.
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
The three vectors above form the triangle AOB. using Law of Cosines , \[ab^{2}=a^{2}+b^{2}2ab\cos \theta\] using properties of dot product. \[ab^{2}=(ab).(ab)\] \[=a.aa.bb.a+b.b\] \[=a^{2}+b^{2}2a.b\] original becomes, \[ab^{2}=a^{2}+b ^{2}2ab\cos \theta\] and, \[a^{2}2a.b+b^{2}=a^{2}+b ^{2}2ab\cos \theta\] now cancel terms which are same and you will got \[a.b=ab\cos \theta\]
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
that is all. Regards, Read my Profile. :D
 2 years ago

fryad_muhammed Group TitleBest ResponseYou've already chosen the best response.0
zor zor supas aziyatm dait
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
kia?
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
what is this language?
 2 years ago

fryad_muhammed Group TitleBest ResponseYou've already chosen the best response.0
what is your language?
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
urdu and english.
 2 years ago

fryad_muhammed Group TitleBest ResponseYou've already chosen the best response.0
I am kurdish
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
ok. now good luck. take care everyone.
 2 years ago

fryad_muhammed Group TitleBest ResponseYou've already chosen the best response.0
I am beginner in physic,thus I want help me for any time if you can my brother?
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
sure sure. i am often available here. you can post your question.
 2 years ago

fryad_muhammed Group TitleBest ResponseYou've already chosen the best response.0
That is all kind of you for every thing.can I recognize you in facebook?
 2 years ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.3
Just skimming through this.... You should recognize that the angle is not 45 degrees because it's a rectangle, not a square, so the values above would not yield the correct answer.
 2 years ago

elica85 Group TitleBest ResponseYou've already chosen the best response.1
good point, i wasn't using 45 though, just used the measurements given. i still need to resolve, haven't got to it yet
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
elica85 are you here?
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
oh yes. so angle is not 45degree. it can be calculated as, \[\tan^{1} (0.01/0.03)=18.43degrees.\] Kindly use this angle instead of 45.
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
thanks to Jemurray3.
 2 years ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.3
elica I assume you are adding the components separately and then using the Pythagorean Theorem to calculate the magnitude of the resultant, right?
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
hi jemurray3
 2 years ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.3
Hi there Shayaan
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
http://openstudy.com/study#/updates/4f245a39e4b0a2a9c2667f2f We need you in mathematics section. kindly help us.
 2 years ago

elica85 Group TitleBest ResponseYou've already chosen the best response.1
thank you everyone, i did get the right answer finally. i was confused about +/. i thought the  charge on negative would make it negative direction going down y, making it double negative...so i was just getting calculations wrong. it was 18 degrees ^^
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.1
you are ever welcome. we are made for help. pleasure.
 2 years ago
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