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elica85

What is the magnitude of the force on the -10 charge in the figure ?

  • 2 years ago
  • 2 years ago

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  1. elica85
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    |dw:1327758982728:dw|

    • 2 years ago
  2. elica85
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    the resultant force should be...|dw:1327759214456:dw| something like that

    • 2 years ago
  3. elica85
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    broke down x and y components for force on + on - and - on - and then added...not getting right answer

    • 2 years ago
  4. fryad_muhammed
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    450*10^-9 N

    • 2 years ago
  5. elica85
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    can you explain?

    • 2 years ago
  6. elica85
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    it's not the right answer

    • 2 years ago
  7. fryad_muhammed
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    why?

    • 2 years ago
  8. Shayaan_Mustafa
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    it is not easy. it is a vector quantity. therefore you must have to consider directions.

    • 2 years ago
  9. Shayaan_Mustafa
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    you have to wait until i solve it for you. ok elicia85?

    • 2 years ago
  10. elica85
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    sure and can you please show steps??

    • 2 years ago
  11. Shayaan_Mustafa
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    yes i will show steps to you. wait. i am here.

    • 2 years ago
  12. elica85
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    ok thank you

    • 2 years ago
  13. Shayaan_Mustafa
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    you are welcome.

    • 2 years ago
  14. Shayaan_Mustafa
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    here is diagram first look at this and understand this.

    • 2 years ago
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  15. Shayaan_Mustafa
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    is this pic making sense to you? if i do anything wrong here then kindly point out me. you too faryad, hei, elicia85 and an unknown person.

    • 2 years ago
  16. elica85
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    looks good

    • 2 years ago
  17. fryad_muhammed
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    thank you Shayan

    • 2 years ago
  18. Shayaan_Mustafa
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    wait i have to go and just come in 2min

    • 2 years ago
  19. Shayaan_Mustafa
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    hello. it is taking too much time for me. lets solve step by step here. ok. force of +15nC will be represented by F15 force of -10nC will be represented by F10 force of -5nC will be represented by F5 ok.

    • 2 years ago
  20. Shayaan_Mustafa
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    now as you can see. on -10nC there are two forces acting on it. 1)F15 which is attractive and at an angle of 45 2)F5 which repulsive.

    • 2 years ago
  21. Shayaan_Mustafa
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    F15 can be resolve into factors. along x-axis and along y-axis.

    • 2 years ago
  22. Shayaan_Mustafa
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    forces along y-axis can be calculated as, F15y=(kq1q2)/r² sin45 and F5y=(kq1q2)/r² forces along x-axis can be calculated as, F15x=(kq1q2)/r² cos45

    • 2 years ago
  23. Shayaan_Mustafa
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    finally. sum forces and you will get your answer.

    • 2 years ago
  24. Shayaan_Mustafa
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    have you got it? it is done.

    • 2 years ago
  25. elica85
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    it's exactly what i did but i will try again

    • 2 years ago
  26. Shayaan_Mustafa
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    can you show your solution?

    • 2 years ago
  27. elica85
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    well you still have to add the F5 on F10 don't you? which will only consist of y direction force

    • 2 years ago
  28. elica85
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    my answer was 4.07*10^-3

    • 2 years ago
  29. Shayaan_Mustafa
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    well you still have to add the F5 on F10 don't you? which will only consist of y direction force on y-axis: F10y=F15sin45 - F5 on x-axis: F10x= -F15x finally, \[F _{10}=\sqrt{(F _{10y})^{2}+(F _{10x})^{2}}\] This is complete.

    • 2 years ago
  30. Shayaan_Mustafa
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    any question?

    • 2 years ago
  31. fryad_muhammed
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    shayan can you help me?

    • 2 years ago
  32. Shayaan_Mustafa
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    of course fryad. although we are brothers. arn't we?

    • 2 years ago
  33. elica85
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    thank you i'll try again!

    • 2 years ago
  34. Shayaan_Mustafa
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    you are ever welcome. Regards, Read my Profile. :D

    • 2 years ago
  35. fryad_muhammed
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    yes ,sure thank you , please prove this for me A.B=cos& |A|.|B|

    • 2 years ago
  36. Shayaan_Mustafa
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    ok w8. let me analyze.

    • 2 years ago
  37. Shayaan_Mustafa
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    The three vectors above form the triangle AOB. using Law of Cosines , \[|a-b|^{2}=|a|^{2}+|b|^{2}-2|a||b|\cos \theta\] using properties of dot product. \[|a-b|^{2}=(a-b).(a-b)\] \[=a.a-a.b-b.a+b.b\] \[=|a|^{2}+|b|^{2}-2a.b\] original becomes, \[|a-b|^{2}=|a|^{2}+|b ^{2}|-2|a||b|\cos \theta\] and, \[|a|^{2}-2a.b+|b|^{2}=|a|^{2}+|b ^{2}|-2|a||b|\cos \theta\] now cancel terms which are same and you will got \[a.b=|a||b|\cos \theta\]

    • 2 years ago
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  38. Shayaan_Mustafa
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    that is all. Regards, Read my Profile. :D

    • 2 years ago
  39. fryad_muhammed
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    zor zor supas aziyatm dait

    • 2 years ago
  40. Shayaan_Mustafa
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    kia?

    • 2 years ago
  41. Shayaan_Mustafa
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    what is this language?

    • 2 years ago
  42. fryad_muhammed
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    what is your language?

    • 2 years ago
  43. Shayaan_Mustafa
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    urdu and english.

    • 2 years ago
  44. fryad_muhammed
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    I am kurdish

    • 2 years ago
  45. Shayaan_Mustafa
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    ok. now good luck. take care everyone.

    • 2 years ago
  46. fryad_muhammed
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    I am beginner in physic,thus I want help me for any time if you can my brother?

    • 2 years ago
  47. Shayaan_Mustafa
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    sure sure. i am often available here. you can post your question.

    • 2 years ago
  48. fryad_muhammed
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    That is all kind of you for every thing.can I recognize you in facebook?

    • 2 years ago
  49. Jemurray3
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    Just skimming through this.... You should recognize that the angle is not 45 degrees because it's a rectangle, not a square, so the values above would not yield the correct answer.

    • 2 years ago
  50. elica85
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    good point, i wasn't using 45 though, just used the measurements given. i still need to resolve, haven't got to it yet

    • 2 years ago
  51. Shayaan_Mustafa
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    elica85 are you here?

    • 2 years ago
  52. Shayaan_Mustafa
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    oh yes. so angle is not 45degree. it can be calculated as, \[\tan^{-1} (0.01/0.03)=18.43degrees.\] Kindly use this angle instead of 45.

    • 2 years ago
  53. Shayaan_Mustafa
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    thanks to Jemurray3.

    • 2 years ago
  54. Jemurray3
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    elica I assume you are adding the components separately and then using the Pythagorean Theorem to calculate the magnitude of the resultant, right?

    • 2 years ago
  55. Shayaan_Mustafa
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    hi jemurray3

    • 2 years ago
  56. Jemurray3
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    Hi there Shayaan

    • 2 years ago
  57. Shayaan_Mustafa
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    http://openstudy.com/study#/updates/4f245a39e4b0a2a9c2667f2f We need you in mathematics section. kindly help us.

    • 2 years ago
  58. elica85
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    thank you everyone, i did get the right answer finally. i was confused about +/-. i thought the - charge on negative would make it negative direction going down y, making it double negative...so i was just getting calculations wrong. it was 18 degrees ^^

    • 2 years ago
  59. Shayaan_Mustafa
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    you are ever welcome. we are made for help. pleasure.

    • 2 years ago
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