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anonymous
 4 years ago
1 =A+2B
8 =2C+B
0 =4A+C
Solve for A, B & C
anonymous
 4 years ago
1 =A+2B 8 =2C+B 0 =4A+C Solve for A, B & C

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Take the third equation and subtract 4A from both sides 4A = C Take 4A and substitute into the second equation so 8 = 2C + B turns into 8 = 2(4A) + B take the first equation and the new equation in the previous line and

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0... subtract the first equation from TWICE new equation 16 = 16A + 2B 1 = A + 2B to get 17 = 17A so A = 1 which means from 4A = C that 4(1) = C = 4 and from the first equation 1 = 1 + 2B or B = 0

phi
 4 years ago
Best ResponseYou've already chosen the best response.0Using elimination, which is very methodical, is a good way to go 1 =A+2B 8 =2C+B 0 =4A+C use elimination. First, put the coefficients in order A B C 1 2 0 1 0 1 2 8 4 0 1 0 multiply the first row by 4 and add to the third row 1 2 0 1 0 2 2 8 0 8 1 4 multiply 2nd row by 4 and add to third row 1 2 0 1 0 2 2 8 0 0 9 36 backsolve (work from bottom up) C= 36/9 = 4 2B 8 = 8, B=0 A +2*0 +0* 4= 1, A=1
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