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anonymous
 4 years ago
Expand the expression in powers of x to x^3
1 4
  
2x+1 4+x^2
anonymous
 4 years ago
Expand the expression in powers of x to x^3 1 4    2x+1 4+x^2

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry, it's mean to be 4 and not 4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think... \[(x^28)/(2x^3+x^2+8x+4)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ahh, shoot, (x^28x), sry

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Um no... it's expansion... not simplifying...

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0\(1/ (2x+1)4/(4+x^2)\) \((4+x^28x4)/( 2x^3+x^2+8x+4)\) \((x^28x)/( 2x^3+x^2+8x+4)\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think you have to do this piece by piece, using \[\frac{1}{1r}=1+r+r^2+r^3 + ...\] or in this case \[\frac{1}{1+x}=1x+x^2x^3+...\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How do you do it that way, satellite?

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0order which grade question is this??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's last year of highschool... so, pretty high (Uni first year)

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0then we'll have to use satellite's method

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok that was wrong, it is just the way you want it. \[\frac{1}{1+2x}=1(2x)+(2x)^2(2x)^3+...\] but we can stop there because you only need first four terms

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{4}{4+x^2}\] is more of a pain because you have to have a one in the denominator, so divide top and bottom by 4 to get \[\frac{1}{1+\frac{x^2}{4}}\] and repeat the process

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0with judicious use of parentheses you get \[\frac{1}{1+\frac{x^2}{4}}=1(\frac{x^2}{4})+(\frac{x^2}{4})^2\] but really we can stop here because you only need up to \[x^3\] for your problem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0your last job is to combine like terms for \[12x+4x^28x^3\left(1\frac{x^2}{4}\right )\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh look, we can even check that it is right, by looking at the first 3 terms here http://www.wolframalpha.com/input/?i=1%2F%282x%2B1%294%2F%284%2Bx^2%29

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It is right :) I know how you got it now. Thank you
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