## anonymous 4 years ago How to do this?

1. anonymous

What?

2. anonymous

|dw:1327765483387:dw|

3. anonymous

Solve for x.

4. anonymous

Use equation editor or draw little smaller

5. anonymous

Where is equation editor?

6. anonymous

Did u get the question?

7. anonymous

No

8. anonymous

The question is : x + [root x+ {root x+ (root x+......)}] = 2

9. anonymous

Solve for x.

10. anonymous

I'm not getting the question

11. anonymous

Wait, I am sending the attachment. Refer question no. 15.

12. anonymous

How do you know I am in FIITJEE

13. anonymous

I just asked u brother. Did u come to Utkarsh 11?

14. anonymous

$x+\sqrt{x+\sqrt{x+\sqrt{x+...}}}=2$ \

15. anonymous

Satellite 73 is absolutely correct. Please solve now.

16. anonymous

that is my guess. is it right?

17. anonymous

Yea, u r right.

18. JamesJ

got this sat?

19. JamesJ

(I certainly did not deserve a medal for that)

20. anonymous

no, but ur answers are always accurate so i gave one ahead of time XD

21. anonymous

i would make a guess to start with $x+\sqrt{\text{blah}}=2$ $\sqrt{\text{blah}}=2-x$ square both sides and get $x+\sqrt{\text{blah}}=4+2x-x^2$ $2=4+2x-x^2$ and then solve the quadratic

22. anonymous

@jamesj i certainly did not deserve a medal for that either...

23. anonymous

Then, we get x = 1 + root 3

24. anonymous

In the answer key, answer is given as = 2 - root 2

25. anonymous

26. anonymous

Reply soon. i have to go!!!!!!!!PLzzzzzzzzzzzzzzzzzzzzzz.

27. JamesJ

There's a sign error in what sat wrote above. We have that $x + \sqrt{stuff} = 2$ hence $\sqrt{stuff} = 2 - x$ Now squaring we have $stuff = x^2 - 4x + 4$ i.e., $2 = x^2 - 4x + 4$ i.e., $x^2 - 4x + 2 = 0$ Now you'll get the answer you're looking for.

28. anonymous