anonymous
  • anonymous
How to do this?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
What?
anonymous
  • anonymous
|dw:1327765483387:dw|
anonymous
  • anonymous
Solve for x.

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More answers

anonymous
  • anonymous
Use equation editor or draw little smaller
anonymous
  • anonymous
Where is equation editor?
anonymous
  • anonymous
Did u get the question?
anonymous
  • anonymous
No
anonymous
  • anonymous
The question is : x + [root x+ {root x+ (root x+......)}] = 2
anonymous
  • anonymous
Solve for x.
anonymous
  • anonymous
I'm not getting the question
anonymous
  • anonymous
Wait, I am sending the attachment. Refer question no. 15.
anonymous
  • anonymous
How do you know I am in FIITJEE
anonymous
  • anonymous
I just asked u brother. Did u come to Utkarsh 11?
anonymous
  • anonymous
\[x+\sqrt{x+\sqrt{x+\sqrt{x+...}}}=2\] \
anonymous
  • anonymous
Satellite 73 is absolutely correct. Please solve now.
anonymous
  • anonymous
that is my guess. is it right?
anonymous
  • anonymous
Yea, u r right.
JamesJ
  • JamesJ
got this sat?
JamesJ
  • JamesJ
(I certainly did not deserve a medal for that)
anonymous
  • anonymous
no, but ur answers are always accurate so i gave one ahead of time XD
anonymous
  • anonymous
i would make a guess to start with \[x+\sqrt{\text{blah}}=2\] \[\sqrt{\text{blah}}=2-x\] square both sides and get \[x+\sqrt{\text{blah}}=4+2x-x^2\] \[2=4+2x-x^2\] and then solve the quadratic
anonymous
  • anonymous
@jamesj i certainly did not deserve a medal for that either...
anonymous
  • anonymous
Then, we get x = 1 + root 3
anonymous
  • anonymous
In the answer key, answer is given as = 2 - root 2
anonymous
  • anonymous
How? Please explain.
anonymous
  • anonymous
Reply soon. i have to go!!!!!!!!PLzzzzzzzzzzzzzzzzzzzzzz.
JamesJ
  • JamesJ
There's a sign error in what sat wrote above. We have that \[ x + \sqrt{stuff} = 2 \] hence \[ \sqrt{stuff} = 2 - x \] Now squaring we have \[ stuff = x^2 - 4x + 4 \] i.e., \[ 2 = x^2 - 4x + 4 \] i.e., \[ x^2 - 4x + 2 = 0 \] Now you'll get the answer you're looking for.
anonymous
  • anonymous
Smart Answer. Thanks a lot!!!!!!!!!

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