anonymous
  • anonymous
Solve 4sin(2y - 0.3) + 5cos(27 - 0.3) = 0, for 0(lesser-than-or-equal-to) y (lesser-than-or-equal-to) "pi" radians.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Tanvi is that 5cos(27-0.3)
anonymous
  • anonymous
sorry, 2y - 0.3, not 27 -_-
anonymous
  • anonymous
hhmm - i dont recall solving one like this before - i'll have to check my list of trig identities - wait a few minutes

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anonymous
  • anonymous
sure, suree, take your time. even if we replace (2y - 0.3) by a, then we would get 4sin(a) + 5cos(a) = 0. oh damn, i got it!!
anonymous
  • anonymous
tats the way to go
anonymous
  • anonymous
i don't know what that means, but it'll become tan (a) = -5/4, and then i'll solve it.
anonymous
  • anonymous
yes - thats an easier way - do you really need anyone to help you tanvidals??!! lol well done
anonymous
  • anonymous
yes, can you give me another value for a??? apart from -0.09 rad?? it needs to be positive.
anonymous
  • anonymous
tan -5/4 - the possible values are between o and 2pi radians are in the second and 4th quadrant so we get pi - 0.9 and 2pi - 0.9
anonymous
  • anonymous
i need between 0 and pi.
anonymous
  • anonymous
yes so a = 2.24 , 5.38 so 2y - 0.3 = 2.24 y = 2.54 / 2 = 1.27 rad a=5.38 will be too big one value for y = 1.27 rad
anonymous
  • anonymous
i needed to go higher than pi for value of a because y must have value 0 to pi
anonymous
  • anonymous
thank youu :)
anonymous
  • anonymous
yw - but i think ill have another coffee to stimulate my brain a bit!
anonymous
  • anonymous
oh - plz click on good answer to close the question if you are happy with the answer
anonymous
  • anonymous
i've just checked the answer on wolfram alpha - it gives it as 1.2727
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=Solve+4sin%282y+-+0.3%29+%2B+5cos%282y+-+0.3%29+%3D+0
anonymous
  • anonymous
thats a good site for verification
anonymous
  • anonymous
run your cursor over the root plot - the red spot on positive x-axis - i gives you this value

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