the sum of the two smallest of five consecutive odd integers is 50 less than the sum of the other three integers. What is the smallest integer?

- anonymous

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- schrodinger

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- Mertsj

The five integers are:
x
x+2
x+4
x+6
x+8

- Mertsj

The sum of the two smallest is x + x+2 or 2x+2

- Mertsj

That sum, 2x+2 is 50 less than the sum of the other three.
The sum of the other three is 3x+18
So we have
2x+2=3x+18-50

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## More answers

- Mertsj

Can you solve that?

- anonymous

ya give me a min and I'll tell you the answer

- anonymous

x=-34

- Mertsj

I got 34 but that is not an odd integer.

- Mertsj

Are you sure the problem said odd?

- anonymous

my mistake it says even

- Mertsj

Did you find you mistake in getting -34?

- anonymous

3x+18-50=2x+2

- anonymous

3x+34=2x

- anonymous

34=-1x

- anonymous

x=-34

- Mertsj

3x+18-50=2x+2
3x-32 = 2x=2
3x=2x+34
x=34

- anonymous

you didn't move the two from the other side cuz 18-50 is -32 then plus 2 is -30

- anonymous

wait I see what you did

- Mertsj

|dw:1327772166498:dw|

- anonymous

got it

- Mertsj

Good girl!!

- anonymous

A man is currently 26yrs older than his son. 12yrs before the current time, the man will be twice as old as his son. what is the current age of the father?

- Mertsj

x= son's age now
x+26 = man's age now
x-12= son's age 12 years ago
x+26-12=man's age 12 years ago=x+14
x+14=2(x-12)

- Mertsj

Can you solve it?

- anonymous

x=52

- Mertsj

i got 38

- anonymous

okay what did I do wrong?

- anonymous

2x+52=2x

- anonymous

28+24=52

- Mertsj

\[x+14=2x-24\]

- anonymous

isn't there two x+14? or just that one?

- Mertsj

|dw:1327773113418:dw|

- Mertsj

So the son is 38, the father is 38+26 or 64
Twelve years the son was 26 and the father was 52
And 52 is twice 26 just like the problem says.

- anonymous

wait soo I got the right answer to begin with?

- Mertsj

If you said the son is 38 you did. Is that what you said?

- anonymous

I said the dad is 52

- Mertsj

Is 38+26 equal to 52?

- anonymous

guess I was wrong

- Mertsj

12 years ago the father was 52. He is now 64 and the problem asks how old the father is now.

- anonymous

of course

- anonymous

A woman is currently 21yrs older than her daughter. Eleven yrs before current time the daughter was 2/3 as old as her mother. What is hte mother's current age?
tell me if I got this partly right........ x+21= daughter's current age x-2/3-11= daughter's age eleven yrs ago

- Mertsj

Start out with x = daughter's age now

- Mertsj

How old is her mother right now?

- anonymous

doesn't say

- anonymous

wait lolx+21 is the mother's age now

- anonymous

can you help me formi it into an equation

- Mertsj

so how old was the daughter 11 years ago?

- anonymous

x-2/3-11

- anonymous

eleven yrs ago she was 2/3rds her mothers age

- Mertsj

How old are you?

- Mertsj

Come on. It's not a hard question.

- anonymous

me?

- Mertsj

yes. I'm trying to help you understand these problems. Could you please just answer the question. It's not a hard one. If you want to make up a number I don't care. I'm not really interested in how old you are.

- anonymous

okay give me some slack here...... ME and math don't get along that well

- anonymous

I'm a freshman in college

- Mertsj

That is NOT a number. How old is your roommate?

- anonymous

ya me and roommates don't work parents paying for private rm here's a number

- anonymous

19

- Mertsj

How old was she 11 years ago?

- anonymous

I prob didn't set the equation up right cuz I didn't get a whole # i got-98/3

- anonymous

x+21=x-2/3-11+x

- Mertsj

x= daughter's age now
x+21=mother's age now
x-11=daughter's age 11 years ago.
x+21-11=x+10 = mother's age 11 years ago.
x-11=2/3(x+10)

- Mertsj

Solve it.

- anonymous

x=55

- anonymous

where did the x+10 come fromthough

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