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anonymous
 4 years ago
f(x)=2x^2+16/x
anonymous
 4 years ago
f(x)=2x^2+16/x

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and i have to use these steps....... 12 britt320042000 This is the asker STEP 1: Factor the numerator and denominator of R and find its domain. If 0 is in the domain, find the yintercept, R(0), and plot it. STEP 2: Write R in lowest terms as p(x)q(x) and find the real zeros of the numerator; that is, find the real solutions of the equation p(x) = 0, if any. These are the xintercepts of the graph. Determine the behavior of the graph of R near each xintercept, using the same procedure as for polynomial functions. Plot each xintercept and indicate the behavior of the graph near it. STEP 3: With R written in lowest terms as p(x)q(x), find the real zeros of the denominator; that is, find the real solutions of the equation q(x) = 0, if any. These determine the vertical asymptotes of the graph. Graph each vertical asymptote using a dashed line. STEP 4: Locate any horizontal or oblique asymptotes using the procedure given in the previous section. Graph the asymptotes using a dashed line. Determine the points, if any, at which the graph of R intersects these asymptotes. Plot any such points. STEP 5: Using the real zeros of the numerator and the denominator of the given equation for R, divide the xaxis into intervals and determine where the graph is above the xaxis and where it is below the xaxis by choosing a number in each interval and evaluating R there. Plot the points found. STEP 6: Analyze the behavior of the graph of R near each asymptote and indicate this behavior on the graph. STEP 7: Put all the information together to obtain the graph of R
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