## anonymous 4 years ago the domain of f(x)=2x^2+16/x

1. Akshay_Budhkar

all real numbers except for x=0

2. Akshay_Budhkar

as function is not defined at x=0

3. anonymous

confused

4. Akshay_Budhkar

ok, when u plug in x= 0 in your function you see that the function turns out to be $16 \over 0$ so its not defined right?

5. anonymous

ok

6. Akshay_Budhkar

if u see the function is defined for all the other values of x