Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Jinnie

  • 2 years ago

A girl standing on the top of a building 200 feet highs throws a water balloon up in the air at a velocity of 30ft/sec. The equation for the height of the water balloon is h(t)=-16t^2 +30t + 200 Find the average velocity of the water balloon between 2 sec and 2.01 sec

  • This Question is Closed
  1. shaan_iitk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    abg velocity would be (h(2) - h(2.01))/(2-2.01)

  2. Jinnie
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how do i find the instantaneous velocity at two seconds and the direction of the water balloon

  3. EdgeOfTheEarth
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    it involves calculus. do you know what a derivative is?

  4. shaan_iitk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    instantaneous vel would be dh/dt (differential wrt t) ...

  5. shaan_iitk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    direction of baloon would be the sign of the instantaneous velocity ..if it is positive then it would be in positive direction of the axis you are measuring your height anf vice versa

  6. Jinnie
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    alright let me enter this into my calc and see

  7. Jinnie
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    stay with me please. i need to know this question

  8. Jinnie
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    am i plugging 2 into t^2 and 2.01 into 30t

  9. shaan_iitk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    no mate you plugging both into the h(t) function ... its like you finding the value of h(t) at 2 and again value of h(t) at 2.01 what class are you in?

  10. Jinnie
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    calc

  11. Jinnie
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok i see

  12. shaan_iitk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    with calc edgeoftheearth meant means calculus .. not calculator.. :)

  13. Jinnie
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i dont get you

  14. shaan_iitk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    do you have exposure in calculus?

  15. Jinnie
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    am i familiar with calculus?

  16. EdgeOfTheEarth
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  17. Jinnie
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    when i plug in 2, i get 196.3 and 2.01, I get 195.6584

  18. EdgeOfTheEarth
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    does that make sense? you are basically finding the change in height (ft) from 2 to 2.01 seconds, and then dividing that by the change in time, .01 s

  19. Jinnie
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok so i subtract 195.6584 from 196.3 and then divide by .01?

  20. EdgeOfTheEarth
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes, but your change in height is a little off.. h(2.01) = 195.6584 and h(2) = 196. 195.6584 - 196 = -0.3416.

  21. Jinnie
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i see

  22. Jinnie
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so for the instantaneous velocity, what must i do? i didnt understand you last time

  23. EdgeOfTheEarth
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    for instantaneous velocity you have to take the derivative of the position function (h(t)).

  24. Jinnie
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i got zero, am i right?

  25. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.