anonymous
  • anonymous
A girl standing on the top of a building 200 feet highs throws a water balloon up in the air at a velocity of 30ft/sec. The equation for the height of the water balloon is h(t)=-16t^2 +30t + 200 Find the average velocity of the water balloon between 2 sec and 2.01 sec
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
abg velocity would be (h(2) - h(2.01))/(2-2.01)
anonymous
  • anonymous
how do i find the instantaneous velocity at two seconds and the direction of the water balloon
anonymous
  • anonymous
it involves calculus. do you know what a derivative is?

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anonymous
  • anonymous
instantaneous vel would be dh/dt (differential wrt t) ...
anonymous
  • anonymous
direction of baloon would be the sign of the instantaneous velocity ..if it is positive then it would be in positive direction of the axis you are measuring your height anf vice versa
anonymous
  • anonymous
alright let me enter this into my calc and see
anonymous
  • anonymous
stay with me please. i need to know this question
anonymous
  • anonymous
am i plugging 2 into t^2 and 2.01 into 30t
anonymous
  • anonymous
no mate you plugging both into the h(t) function ... its like you finding the value of h(t) at 2 and again value of h(t) at 2.01 what class are you in?
anonymous
  • anonymous
calc
anonymous
  • anonymous
ok i see
anonymous
  • anonymous
with calc edgeoftheearth meant means calculus .. not calculator.. :)
anonymous
  • anonymous
i dont get you
anonymous
  • anonymous
do you have exposure in calculus?
anonymous
  • anonymous
am i familiar with calculus?
anonymous
  • anonymous
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anonymous
  • anonymous
when i plug in 2, i get 196.3 and 2.01, I get 195.6584
anonymous
  • anonymous
does that make sense? you are basically finding the change in height (ft) from 2 to 2.01 seconds, and then dividing that by the change in time, .01 s
anonymous
  • anonymous
ok so i subtract 195.6584 from 196.3 and then divide by .01?
anonymous
  • anonymous
Yes, but your change in height is a little off.. h(2.01) = 195.6584 and h(2) = 196. 195.6584 - 196 = -0.3416.
anonymous
  • anonymous
i see
anonymous
  • anonymous
so for the instantaneous velocity, what must i do? i didnt understand you last time
anonymous
  • anonymous
for instantaneous velocity you have to take the derivative of the position function (h(t)).
anonymous
  • anonymous
i got zero, am i right?

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