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Jinnie

A girl standing on the top of a building 200 feet highs throws a water balloon up in the air at a velocity of 30ft/sec. The equation for the height of the water balloon is h(t)=-16t^2 +30t + 200 Find the average velocity of the water balloon between 2 sec and 2.01 sec

  • 2 years ago
  • 2 years ago

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  1. shaan_iitk
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    abg velocity would be (h(2) - h(2.01))/(2-2.01)

    • 2 years ago
  2. Jinnie
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    how do i find the instantaneous velocity at two seconds and the direction of the water balloon

    • 2 years ago
  3. EdgeOfTheEarth
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    it involves calculus. do you know what a derivative is?

    • 2 years ago
  4. shaan_iitk
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    instantaneous vel would be dh/dt (differential wrt t) ...

    • 2 years ago
  5. shaan_iitk
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    direction of baloon would be the sign of the instantaneous velocity ..if it is positive then it would be in positive direction of the axis you are measuring your height anf vice versa

    • 2 years ago
  6. Jinnie
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    alright let me enter this into my calc and see

    • 2 years ago
  7. Jinnie
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    stay with me please. i need to know this question

    • 2 years ago
  8. Jinnie
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    am i plugging 2 into t^2 and 2.01 into 30t

    • 2 years ago
  9. shaan_iitk
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    no mate you plugging both into the h(t) function ... its like you finding the value of h(t) at 2 and again value of h(t) at 2.01 what class are you in?

    • 2 years ago
  10. Jinnie
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    calc

    • 2 years ago
  11. Jinnie
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    ok i see

    • 2 years ago
  12. shaan_iitk
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    with calc edgeoftheearth meant means calculus .. not calculator.. :)

    • 2 years ago
  13. Jinnie
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    i dont get you

    • 2 years ago
  14. shaan_iitk
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    do you have exposure in calculus?

    • 2 years ago
  15. Jinnie
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    am i familiar with calculus?

    • 2 years ago
  16. EdgeOfTheEarth
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    • 2 years ago
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  17. Jinnie
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    when i plug in 2, i get 196.3 and 2.01, I get 195.6584

    • 2 years ago
  18. EdgeOfTheEarth
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    does that make sense? you are basically finding the change in height (ft) from 2 to 2.01 seconds, and then dividing that by the change in time, .01 s

    • 2 years ago
  19. Jinnie
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    ok so i subtract 195.6584 from 196.3 and then divide by .01?

    • 2 years ago
  20. EdgeOfTheEarth
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    Yes, but your change in height is a little off.. h(2.01) = 195.6584 and h(2) = 196. 195.6584 - 196 = -0.3416.

    • 2 years ago
  21. Jinnie
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    i see

    • 2 years ago
  22. Jinnie
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    so for the instantaneous velocity, what must i do? i didnt understand you last time

    • 2 years ago
  23. EdgeOfTheEarth
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    for instantaneous velocity you have to take the derivative of the position function (h(t)).

    • 2 years ago
  24. Jinnie
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    i got zero, am i right?

    • 2 years ago
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