A girl standing on the top of a building 200 feet highs throws a water balloon up in the air at a velocity of 30ft/sec. The equation for the height of the water balloon is h(t)=-16t^2 +30t + 200
Find the average velocity of the water balloon between 2 sec and 2.01 sec

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abg velocity would be (h(2) - h(2.01))/(2-2.01)

how do i find the instantaneous velocity at two seconds and the direction of the water balloon

it involves calculus. do you know what a derivative is?

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