At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

abg velocity would be (h(2) - h(2.01))/(2-2.01)

how do i find the instantaneous velocity at two seconds and the direction of the water balloon

it involves calculus. do you know what a derivative is?

instantaneous vel would be dh/dt (differential wrt t) ...

alright let me enter this into my calc and see

stay with me please. i need to know this question

am i plugging 2 into t^2 and 2.01 into 30t

calc

ok i see

with calc edgeoftheearth meant means calculus .. not calculator.. :)

i dont get you

do you have exposure in calculus?

am i familiar with calculus?

when i plug in 2, i get 196.3 and 2.01, I get 195.6584

ok so i subtract 195.6584 from 196.3 and then divide by .01?

i see

so for the instantaneous velocity, what must i do? i didnt understand you last time

for instantaneous velocity you have to take the derivative of the position function (h(t)).

i got zero, am i right?