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Jinnie
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A girl standing on the top of a building 200 feet highs throws a water balloon up in the air at a velocity of 30ft/sec. The equation for the height of the water balloon is h(t)=16t^2 +30t + 200
Find the average velocity of the water balloon between 2 sec and 2.01 sec
 2 years ago
 2 years ago
Jinnie Group Title
A girl standing on the top of a building 200 feet highs throws a water balloon up in the air at a velocity of 30ft/sec. The equation for the height of the water balloon is h(t)=16t^2 +30t + 200 Find the average velocity of the water balloon between 2 sec and 2.01 sec
 2 years ago
 2 years ago

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shaan_iitk Group TitleBest ResponseYou've already chosen the best response.1
abg velocity would be (h(2)  h(2.01))/(22.01)
 2 years ago

Jinnie Group TitleBest ResponseYou've already chosen the best response.0
how do i find the instantaneous velocity at two seconds and the direction of the water balloon
 2 years ago

EdgeOfTheEarth Group TitleBest ResponseYou've already chosen the best response.0
it involves calculus. do you know what a derivative is?
 2 years ago

shaan_iitk Group TitleBest ResponseYou've already chosen the best response.1
instantaneous vel would be dh/dt (differential wrt t) ...
 2 years ago

shaan_iitk Group TitleBest ResponseYou've already chosen the best response.1
direction of baloon would be the sign of the instantaneous velocity ..if it is positive then it would be in positive direction of the axis you are measuring your height anf vice versa
 2 years ago

Jinnie Group TitleBest ResponseYou've already chosen the best response.0
alright let me enter this into my calc and see
 2 years ago

Jinnie Group TitleBest ResponseYou've already chosen the best response.0
stay with me please. i need to know this question
 2 years ago

Jinnie Group TitleBest ResponseYou've already chosen the best response.0
am i plugging 2 into t^2 and 2.01 into 30t
 2 years ago

shaan_iitk Group TitleBest ResponseYou've already chosen the best response.1
no mate you plugging both into the h(t) function ... its like you finding the value of h(t) at 2 and again value of h(t) at 2.01 what class are you in?
 2 years ago

shaan_iitk Group TitleBest ResponseYou've already chosen the best response.1
with calc edgeoftheearth meant means calculus .. not calculator.. :)
 2 years ago

Jinnie Group TitleBest ResponseYou've already chosen the best response.0
i dont get you
 2 years ago

shaan_iitk Group TitleBest ResponseYou've already chosen the best response.1
do you have exposure in calculus?
 2 years ago

Jinnie Group TitleBest ResponseYou've already chosen the best response.0
am i familiar with calculus?
 2 years ago

Jinnie Group TitleBest ResponseYou've already chosen the best response.0
when i plug in 2, i get 196.3 and 2.01, I get 195.6584
 2 years ago

EdgeOfTheEarth Group TitleBest ResponseYou've already chosen the best response.0
does that make sense? you are basically finding the change in height (ft) from 2 to 2.01 seconds, and then dividing that by the change in time, .01 s
 2 years ago

Jinnie Group TitleBest ResponseYou've already chosen the best response.0
ok so i subtract 195.6584 from 196.3 and then divide by .01?
 2 years ago

EdgeOfTheEarth Group TitleBest ResponseYou've already chosen the best response.0
Yes, but your change in height is a little off.. h(2.01) = 195.6584 and h(2) = 196. 195.6584  196 = 0.3416.
 2 years ago

Jinnie Group TitleBest ResponseYou've already chosen the best response.0
so for the instantaneous velocity, what must i do? i didnt understand you last time
 2 years ago

EdgeOfTheEarth Group TitleBest ResponseYou've already chosen the best response.0
for instantaneous velocity you have to take the derivative of the position function (h(t)).
 2 years ago

Jinnie Group TitleBest ResponseYou've already chosen the best response.0
i got zero, am i right?
 2 years ago
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