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anonymous
 4 years ago
A girl standing on the top of a building 200 feet highs throws a water balloon up in the air at a velocity of 30ft/sec. The equation for the height of the water balloon is h(t)=16t^2 +30t + 200
Find the average velocity of the water balloon between 2 sec and 2.01 sec
anonymous
 4 years ago
A girl standing on the top of a building 200 feet highs throws a water balloon up in the air at a velocity of 30ft/sec. The equation for the height of the water balloon is h(t)=16t^2 +30t + 200 Find the average velocity of the water balloon between 2 sec and 2.01 sec

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0abg velocity would be (h(2)  h(2.01))/(22.01)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how do i find the instantaneous velocity at two seconds and the direction of the water balloon

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it involves calculus. do you know what a derivative is?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0instantaneous vel would be dh/dt (differential wrt t) ...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0direction of baloon would be the sign of the instantaneous velocity ..if it is positive then it would be in positive direction of the axis you are measuring your height anf vice versa

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0alright let me enter this into my calc and see

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0stay with me please. i need to know this question

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0am i plugging 2 into t^2 and 2.01 into 30t

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no mate you plugging both into the h(t) function ... its like you finding the value of h(t) at 2 and again value of h(t) at 2.01 what class are you in?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0with calc edgeoftheearth meant means calculus .. not calculator.. :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do you have exposure in calculus?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0am i familiar with calculus?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0when i plug in 2, i get 196.3 and 2.01, I get 195.6584

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0does that make sense? you are basically finding the change in height (ft) from 2 to 2.01 seconds, and then dividing that by the change in time, .01 s

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so i subtract 195.6584 from 196.3 and then divide by .01?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, but your change in height is a little off.. h(2.01) = 195.6584 and h(2) = 196. 195.6584  196 = 0.3416.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so for the instantaneous velocity, what must i do? i didnt understand you last time

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for instantaneous velocity you have to take the derivative of the position function (h(t)).

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got zero, am i right?
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