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anonymous

  • 4 years ago

A pawnbroker buys a tv set and a computer for $600. He sells the comouter at a markup of 30% and the tv set at a markup of 20%. If he makes a profit of $165 on the sale of the two items, hwat did he pay for the computer?

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  1. Hero
    • 4 years ago
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    t + c = 600 1.30t+ 1.20c = 765 Solve the system.

  2. anonymous
    • 4 years ago
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    ooo soo all I was missing was the ones on the %s thought my answer was off

  3. Hero
    • 4 years ago
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    t(1 + .30) = t + .30t = 1.30t c(1+.20) = c + .20c = 1.20c

  4. Hero
    • 4 years ago
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    The markups of course is what allows him to make a profit.

  5. anonymous
    • 4 years ago
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    soo is it 1.3t+1.2c=765?

  6. Hero
    • 4 years ago
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    For the second equation, yes

  7. anonymous
    • 4 years ago
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    first equation is t+c=600 then the second one is 1.3t+1.2c=765

  8. Hero
    • 4 years ago
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    Correct

  9. anonymous
    • 4 years ago
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    the profit is 165 not 765

  10. anonymous
    • 4 years ago
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    but I know how to solve one equation and pug it into the other=)

  11. Hero
    • 4 years ago
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    765 is the total amount he will have however.

  12. Hero
    • 4 years ago
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    If you have $600, then spend it, would reselling and making only $165 back be a profit?

  13. anonymous
    • 4 years ago
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    Ya but they're wanting to know how much he paid for the computer not the total profit

  14. Hero
    • 4 years ago
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    In order to do that, you have to find the value of variable c. In order to find variable c, you have to set up the proper equations.

  15. Hero
    • 4 years ago
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    Marie, I don't understand why you are disputing my setup.

  16. anonymous
    • 4 years ago
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    you set it up right I'm just questioning whether it should be 765 or 165

  17. Hero
    • 4 years ago
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    It goes back to that same thing I was telling you earlier. If you put 165, it would mean he only made 165 after reselling. Making only 165 after reselling is not a profit because 165 < 600 A profit only exists if x > 600 765 > 600, which is a profit of 165 The first equation represents the amount of each item costs equaling their total cost. The second equation represents the re-sell prices equaling the total amount made including the original amount plus the profit.

  18. Hero
    • 4 years ago
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    There's no other way to do this, sorry.

  19. anonymous
    • 4 years ago
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    7050/11?

  20. Hero
    • 4 years ago
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    And what might that be?

  21. anonymous
    • 4 years ago
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    vs. 1050/11

  22. anonymous
    • 4 years ago
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    the first fraction is what I got the first time using your way the second one is my way

  23. Hero
    • 4 years ago
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    FYI, prices are not given in fractions. Put the answer in decimal form up accurate to two decimal places

  24. Hero
    • 4 years ago
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    That is not correct: Wolfram provides the correct values: http://www.wolframalpha.com/input/?i=t+%2B+c+%3D+600+and+1.30t%2B+1.20c+%3D+765

  25. anonymous
    • 4 years ago
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    okay lol I trust you lol I won't argue next time

  26. anonymous
    • 4 years ago
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    My book says 450

  27. Hero
    • 4 years ago
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    Yeah, I originally mixed up the variables at the beginning. But 450 and 150 are the answers. If you wanted to nitpick at me, you should have nitpicked me for mixing up the variables :P

  28. Hero
    • 4 years ago
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    It was supposed to be: c + t = 600 1.30c+ 1.20t = 765 That's the only mistake I made.

  29. Hero
    • 4 years ago
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    But everything else is right.

  30. anonymous
    • 4 years ago
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    Hey I don't mean to pick on you I just wanna understand this stuff

  31. Hero
    • 4 years ago
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    I know. Wanna go to vyew?

  32. anonymous
    • 4 years ago
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    ?

  33. Hero
    • 4 years ago
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    Vyew = Collaborative Online Classroom

  34. anonymous
    • 4 years ago
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    Where has this been hiding all this time?

  35. Hero
    • 4 years ago
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    lol

  36. Hero
    • 4 years ago
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    It's not a replacement for open study, but it's a great supplement if you want to learn stuff.

  37. anonymous
    • 4 years ago
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    cool

  38. Hero
    • 4 years ago
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    Click the link ^

  39. anonymous
    • 4 years ago
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    I'm not getting the answer though lol I re-did the variables

  40. Hero
    • 4 years ago
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    I can show you how

  41. anonymous
    • 4 years ago
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    in the other site?

  42. Hero
    • 4 years ago
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    Click the link I sent

  43. Hero
    • 4 years ago
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    Yes

  44. anonymous
    • 4 years ago
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    k

  45. anonymous
    • 4 years ago
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    grait job

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