anonymous
  • anonymous
Factor:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
im waiting :P
anonymous
  • anonymous
\[5yz ^{2}-35yz+10y ^{2}z\]
anonymous
  • anonymous
5 yz ( 5z - 7 + 2y)

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anonymous
  • anonymous
WOoOOOooooOooooOooooo :P
anonymous
  • anonymous
5yz(z - 7 + 2y)
anonymous
  • anonymous
wait...-.- its z not 5z inside the bracket
anonymous
  • anonymous
5 yz ( z - 7 + 2y) soorry
anonymous
  • anonymous
x(y-3) -4(y-3)
anonymous
  • anonymous
you want us to factor that?
anonymous
  • anonymous
do yu simplify it first
anonymous
  • anonymous
and ya factor it
anonymous
  • anonymous
its already factored tho: i guess you can use distributive property and then factor it as a whole
anonymous
  • anonymous
(y-3) (x-4)?
anonymous
  • anonymous
is tht the ans
anonymous
  • anonymous
my bad :P yes it is
anonymous
  • anonymous
Go Charmi :D
anonymous
  • anonymous
^__^
anonymous
  • anonymous
lol any other ones :P
anonymous
  • anonymous
2mn+3mp-4n-6p
anonymous
  • anonymous
2n(m-2) + 3p (m-2)
anonymous
  • anonymous
well for this one you have to find a variable thats common to all the coefficients but i dont think its possible to factor this
anonymous
  • anonymous
(m-2) (2n+3p)
anonymous
  • anonymous
wait
anonymous
  • anonymous
yeah use grouping :O
anonymous
  • anonymous
im losing myself
anonymous
  • anonymous
so is it right?
anonymous
  • anonymous
aha
anonymous
  • anonymous
\[x^{2}-12x+20\]
anonymous
  • anonymous
= 2mn+3mp-4n-6p = (2mn - 4n) + ( 3mp - 6p) = 2n( m - 2) + 3p (m - 2) = (2n + 3p) (m-2)
anonymous
  • anonymous
\[x ^{2} - 12x + 20 \]
anonymous
  • anonymous
yup
anonymous
  • anonymous
\[x ^{2} - 10x - 2x + 20 \]\[(x ^{2} - 2x) + (-10x +20)\] \[x(x-2) -10 (x - 2)\] \[(x - 10) (x - 2)\]
anonymous
  • anonymous
i didnt lose myself :P
anonymous
  • anonymous
yu need 2 numbers tht multiply to 20 and add to 6 right
anonymous
  • anonymous
two numbers that add to 12 and multiply to 20 *
anonymous
  • anonymous
not 6
anonymous
  • anonymous
oh my bad :P
anonymous
  • anonymous
lol dw we all make mistakes P:
anonymous
  • anonymous
im lost :/
anonymous
  • anonymous
on what yu did
anonymous
  • anonymous
umm so basically what i did is that i found that -2 x -10 is equal to positive 20 and add to -12 (negative)x(negative) = positive
anonymous
  • anonymous
oh ok :P
anonymous
  • anonymous
thanks :D
anonymous
  • anonymous
and r yu sure its not (x-2) (x-10)
anonymous
  • anonymous
or it doesnt matter wht way yu put it as
anonymous
  • anonymous
it doesnt really matter as long as you can get the equation you started with i believe it looks better for communication the way you put it
anonymous
  • anonymous
\[y^{2}+3y-18\]
anonymous
  • anonymous
ok for this one you want a number that adds up to 3 and multiplies to get -18 so you're gonna need a negative and a positive number
anonymous
  • anonymous
any ideas of multiples
anonymous
  • anonymous
i was stuck here: y(y+6) -3 (y+6)
anonymous
  • anonymous
wud it be (y+6) (y-3)
anonymous
  • anonymous
someone cheer for her that's right you had the answer the whole time <3
anonymous
  • anonymous
WOOOOO:P
anonymous
  • anonymous
buhh cant yu still divide it cause theres a 3 and a 6?
anonymous
  • anonymous
or jus leave it like tht :P
anonymous
  • anonymous
lol i believe you can leave it like that :D
anonymous
  • anonymous
aha ok :P
anonymous
  • anonymous
\[x^{2}-18\]
anonymous
  • anonymous
shud i leave the middle number as 0
anonymous
  • anonymous
what do you think this one is
anonymous
  • anonymous
how wud yu do this i forgot :$
anonymous
  • anonymous
(a - b) (a+ b) the middle number is eliminated :)
anonymous
  • anonymous
(x-6) (x+6)?
anonymous
  • anonymous
no wait (x-6) (x+3)
anonymous
  • anonymous
i believe the middle number is missing cuz you cant factor that
anonymous
  • anonymous
yu cant?
anonymous
  • anonymous
so yu dun do nytiin to it?
anonymous
  • anonymous
well no matter how much we factor it it wont match the question after factoring
anonymous
  • anonymous
good job dada

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