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anonymous
 4 years ago
find the derivative of g(x)= 4sqrt(x)+3
anonymous
 4 years ago
find the derivative of g(x)= 4sqrt(x)+3

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lalaly
 4 years ago
Best ResponseYou've already chosen the best response.4\[\large{g'(x) =4 \times \frac{1}{2} x^{\frac{1}{2}}} = \frac{2}{\sqrt{x}}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think it would be 2/sqrt(x)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first convert the square root to a fractional index = 4x^(1/2) + 3 derivative = 4 * (1/2) x ^(1/2  1) = 2 x(1/2) or 2 / sqrtx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why did you have (1/21)...where did the 1 come from?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0we used the general formula for the derivative of if f(x) = ax^n f'(x) = an x^(n1)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0jimmy could you help me with this one...its confusing. A girl standing on the top of a building 200 feet highs throws a water balloon up in the air at a velocity of 30ft/sec. The equation for the height of the water balloon is h(t)=16t^2 +30t + 200 find the instantaneous velocity at two seconds and the direction of the water balloon

phi
 4 years ago
Best ResponseYou've already chosen the best response.0instantaneous velocity is dh/dt take the derivative with respect to t to get a new equation then sub in t=2 to find the velocity

phi
 4 years ago
Best ResponseYou've already chosen the best response.0if you get +, the balloon is going higher. if you get a negative number, the balloon is falling

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can someone please demonstrate that

phi
 4 years ago
Best ResponseYou've already chosen the best response.0find the derivative term by term use if f(t) = a*t^n f'(t) = a*n* t^(n1) just like Jim did up above

phi
 4 years ago
Best ResponseYou've already chosen the best response.0h(t)=16t^2 +30t + 200 first find the derivative of 16 t^2 using the rule

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.030t is already reduce, isnt it?

phi
 4 years ago
Best ResponseYou've already chosen the best response.0you start with 16t^2 +30t + 200 then term by term 2* 16 * t^ (21) 30*1* t^(11) 200 * 0 * t(01)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh i see so when i have 32t + 1 + 0...do i just plug in 2 to find the instantaneous velocity into t

phi
 4 years ago
Best ResponseYou've already chosen the best response.0of course nobody uses the exponent rule to find the derivative of a constant. We know it is zero.

phi
 4 years ago
Best ResponseYou've already chosen the best response.0now recheck : derivative with respect to t of : 30 t = ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0t^0= 1 therefore, 30t = 1?

phi
 4 years ago
Best ResponseYou've already chosen the best response.0use the rule: d/dt (30 t^1) = 1*30*t^(11) = 1*30*1 = ??

phi
 4 years ago
Best ResponseYou've already chosen the best response.0so the derivative of 16t^2 +30t + 200 = ?

phi
 4 years ago
Best ResponseYou've already chosen the best response.0adding 0 is not usually done . I mean leave it off, because it does not change anything

phi
 4 years ago
Best ResponseYou've already chosen the best response.0so now you have h'(t) = 32t + 30 change in height with respect to time (velocity for this problem= 32t + 30

phi
 4 years ago
Best ResponseYou've already chosen the best response.0find the instantaneous velocity at two seconds and the direction of the water balloon this means replace t with 2 in your equation to find the velocity at time t=2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i did and i got 34

phi
 4 years ago
Best ResponseYou've already chosen the best response.0you got 34 ft/sec (don't forget the units) the negative sign means which direction? Here is how we know which direction: A girl throws a water balloon *up* in the air at a velocity of +30ft/sec. The problem says +30ft/sec is up, so a 34 ft/sec must be which direction?

phi
 4 years ago
Best ResponseYou've already chosen the best response.0I hope it makes sense. But you have answered the entire question.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah it really did. thanks for taking the time.
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